Question

The fastest pitched baseball was clocked at 47 m/s. Assume that the pitcher exerted his force (assumed to be horizontal and constant) over a distance of 1.0 mm, and a baseball has a mass of 145 g.
Required:
a. Draw a free-body diagram of the ball during the pitch.
b. What force did the pitcher exert on the ball during this record-setting pitch?
c. Estimate the force in part b as a fraction of the pitcher's weight.

Answer 1

Answer:

Following are the solution to the given points:

Explanation:

For point a:

Find the schematic of the empty body and in attachment. Upon on ball during the pitch only two forces act:

The strength of the pitcher F is applied that operates horizontally. Its gravity force acting on an object is termed weight, which value is where m denotes mass, and g the acceleration of gravity.

For point b:

$160.2\ N$

First, they must find that ball's acceleration. You can use the SUVAT equation to achieve that

where

$v = 47\ \frac{m}{s} \\\\u = 0 \\\\a =?\\\\d = 1.0 \ m$

Solving for a,

$a=\frac{v^2-u^2}{2d}=\frac{47^2-0}{2(1.0)}=1104.5 \ \frac{m}{s^2}$

Calculating the mass:

$m = 145 g = 0.145 kg$

Calculating the force:

$F=ma=0.145 \times 1104.5= 160.2 \ N$

 For point c:

0.195 times the pitcher's weight

$m = 84 \ kg \\\\g = 9.8\ \frac{m}{s^2}$

Solving for W:

$W=84 \times 9.8= 823.2 \ N$

Now the force of Part B could be defined as the fraction of the mass of the pitcher:  

$\frac{F}{W}=\frac{160.2}{823.3}=0.195$