Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance.
E = kQ / d²
k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m
Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²
Electric field at the test charge is 921600000 N/C
-- Volume . . . made out of 3 dimensions of length
-- Density . . . made out of mass, and 3 dimensions of length
-- Area . . . made out of 2 dimensions of length
-- Acceleration . . . made out of length and time
<em>Mass</em> is not made out of anything else. It's fundamental. A few other fundamental things are length, time, and electric charge.
Answer:
I font now but I think its 2.0 + 78 w -60
Answer:
2.96×10⁸ m/s
Explanation:
Speed = distance / time
v = (2 × 3.85×10⁸ m) / (2.60 s)
v = 2.96×10⁸ m/s
