Answer:
3960.4 bacteria
Step-by-step explanation:
The formula to solve the above question is given as:
P(t) = Po (2) ^t/k
P(t) = Population after time t = ?
Po = Initial population = 650 bacteria
t = Time in days = 7.3 days
k = doubling time = 2.8 days
P(t) = 650 × (2)^7.3/2.8
P(t) = 650 × 2^2.6071428571
P(t) = 650 × 6.0929582599
P(t) = 3960.4228689 bacteria.
Approximately = 3960.4 bacteria
Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.
Answer:
its b because i took a test
Step-by-step explanation:
You cannot find x.
Because both phrases are to the power of 0, we know that it is essentially 1*1
So:
(3x - 8)^0 (4x - 23)^0 = 1
Answer:
(x-6)^3x-5 =6
Step-by-step explanation:
logb a=c ------> b^c =a
I think it is 90
Hope this help you?!
