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Margaret [11]
4 years ago
8

Verify the identity. sin quantity x plus pi divided by two = cos x

Mathematics
1 answer:
Svetach [21]4 years ago
5 0
\bf sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\\\\\
\textit{also recall that }cos\left( \frac{\pi }{2} \right)=0\qquad \qquad sin\left( \frac{\pi }{2} \right)=1\\\\
-------------------------------\\\\
sin\left( x+\frac{\pi }{2} \right)\implies sin(x)cos\left( \frac{\pi }{2} \right)+cos(x)sin\left( \frac{\pi }{2} \right)
\\\\\\
sin(x)\cdot 0+cos(x)\cdot 1\implies \boxed{cos(x)}
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To visit her grandmother, Melek takes a motorcycle 3.8 kilometers and a horse 3.32 kilometers. In total, the journey takes 50.54
lbvjy [14]

Answer:

Therefore, total number of Kilometers Melek covered =3.3 + 3.32 = 6.62 kilometers.

Step-by-step explanation:

Distance covered by motorcycle = 3.8 kilometers.

Distance covered by horse = 3.32 kilometers.

Total time taken to complete the journey = 50.54 minutes.

We need to find the total number of kilometers Melek took the journey.

We are given time. But we need not to do anything with given time.

We just need to add the journey took by motorcycle and journey took by horse.

---------------------------------------------------------------------------------------------------------------

8 0
3 years ago
In a recent survey of college professors, it was found that the average amount of money spent on entertainment each week was nor
Alenkinab [10]

Answer:

0.0918

Step-by-step explanation:

We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The mean and standard deviation of average spending of sample size 25 are

μxbar=μ=95.25

σxbar=σ/√n=27.32/√25=27.32/5=5.464.

So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The z-score associated with average spending $102.5

Z=[Xbar-μxbar]/σxbar

Z=[102.5-95.25]/5.464

Z=7.25/5.464

Z=1.3269=1.33

We have to find P(Xbar>102.5).

P(Xbar>102.5)=P(Z>1.33)

P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)

P(Xbar>102.5)=0.5-0.4082

P(Xbar>102.5)=0.0918.

Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.

5 0
4 years ago
If m&lt;mkl=83. m&lt;jkl=127. and m&lt;jkm=(9x-10). find the value of x
kirza4 [7]

MKL = 83, JKL = 127, JKM = 9x - 10        <em>given</em>

JKL + MKL = JKM                                    <em>angle addition postulate</em>

127 +  83  = 9x - 10                                 <em>substitution</em>

       210   = 9x - 10                                  <em>simplify (add like terms)</em>

       220  = 9x                                          <em>addition property of equality</em>

        \frac{220}{9} = x

3 0
4 years ago
Solve the following problems. Reduce your answers to their simplest form. a. 13⁄41 + 27⁄82 b. 3 5⁄24 + 6 7⁄24 + 4 9⁄24 c. 5 2⁄3
KATRIN_1 [288]
<span>13⁄41 + 27⁄82 = 26/82 + 27/82 = 53/82

3 5/24 + 6 7/24 + 4 9/24 = 13 20/24 = 13 5/6

</span><span>5 2⁄3 + 29⁄69 + 6 21⁄23 = 5 46/69 + 29/69 + 6 63/69 = 11 138/69 = 13
</span>
<span>3 9⁄10 + 4⁄9 + 7⁄45 + 4 = 3 81/90 + 40/90 + 14/90 + 4 = 7 135/90 = 8 1/2

</span><span>6 – 7⁄15 = 5 15/15 - 7/15 = 5 6/15

</span><span>11 3⁄8 – 7⁄8 = 10 11/8 - 7/8 = 10 4/8 = 10 1/2

</span><span> 7 1⁄6 – 3 4⁄9 = 7 9/54 - 3 18/54 = 6 63/54 - 3 18/54 = 3 45/54 = 3 5/6
</span>
<span>5 3⁄8 – 3 2⁄5 = 5 15/40 - 3 16/40 = 4 55/40 - 3 16/40 = 1 39/40</span>
4 0
3 years ago
Read 2 more answers
Simplify: sin^2xcos^2x-cos^2x
shtirl [24]

Answer:

-cos^4(x)

Step-by-step explanation:

Step 1: Use the Pythagorean identity : 1=cos^2(x) + sin^2(x)

1-sin^2(x) = cos^2(x)

-1+sin^2(x) = -cos^2(x)

cos^2(x) (-cos^2(x))

Step 2: Factor out common terms cos^2(x)

cos^2(x) (sin^2(x)-1)

Ans: -cos^4(x)

8 0
2 years ago
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