One-fourth the sum of 1 and what number is one-half the sum of 2 and 1/2 ?

10 quarters 17 dimes 40 nickels 15 pennies answer

Oliga [24]

If the given quantities are 10 quarters 17 dimes 40 nickels 15 pennies then the total money would be 6.35 dollars.

<h3>What is the fundamental principle of multiplication?</h3>

If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

Quarters are worth .25 of a dollar

10 x .25 = 2.5

Dimes are worth .10 of a dollar

17 x .10 = 1.7

Nickels are worth .05 of a dollar

40 x .05 = 2

Pennies are worth .01 of a dollar

15 x .01 = 0.15

Add this together

2.5 + 1.7 + 2 + 0.15

= 6.35

Learn more about multiplication;

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4 0

2 years ago

A person bought a water tank of circular base having the radius 1.05 meter and height 3.5 meter for the use of own house from th

Anastasy [175]

Answer:

I am not very sure is my answer correct or not, sorry

Hope that I can help you

8 0

3 years ago

A research group wants to know if the online platform to play Settlers of Catan is being accessed more after the stay at home or

Gre4nikov [31]

Answer:

a) The P-value is 0.

At a significance level of 0.05, there is enough evidence to support the claim that the online platform was accessed significantly more so than before the stay at home order.

b) Effect size d = 0.77

Medium.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the online platform was accessed significantly more so than before the stay at home order.

Then, the null and alternative hypothesis are:

$H_0: \mu=1000\\\\H_a:\mu> 1000$

The significance level is 0.05.

The sample has a size n=108000.

The sample mean is M=1378.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=489.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{489}{\sqrt{108000}}=1.488

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1378-1000}{1.488}=\dfrac{378}{1.488}=254.036

The degrees of freedom for this sample size are:

$df=n-1=108000-1=107999$

This test is a right-tailed test, with 107999 degrees of freedom and t=254.036, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t>254.036)=0$

As the P-value (0) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that the online platform was accessed significantly more so than before the stay at home order.

The effect size can be estimated with the Cohen's d.

This can be calculated as:

$d=\dfrac{M-\mu}{\sigma}=\dfrac{1378-1000}{489}=\dfrac{378}{489}=0.77$

The values of Cohen's d between 0.2 and 0.8 are considered "Medium", so in this case, the effect size d=0.77 is medium.

5 0

4 years ago

A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr

Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at $27 mi/hr$ in for two hours. Therefore, the side $a$ is:

$a=(27 mi/hr)(2 hr)=54mi$

- The second ship travels at $18 mi/hr$ for $1.5 hours$ . Therefore, the side $b$ is:

$b=(18mi/hr)(1.5hr)=27mi$

- Now, you can calculate $c$ :

$c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi$

The answer is: $44 miles$

8 0

3 years ago

Someone please explain this question PART "b) i" ONLY!!!

Gnom [1K]

<h3>Answer: (n-1)^2</h3>

This is because we have a list of perfect squares 0,1,4,9,...

We use n-1 in place of n because we're shifting things one spot to the left, since we start at 0 instead of 1.

In other words, if the answer was n^2, then the first term would be 1^2 = 1, the second term would be 2^2 = 4, and so on. But again, we started with 0^2 = 0, so that's why we need the n-1 shift.

You can confirm this is the case by plugging n = 1 into (n-1)^2 and you should find the result is 0^2 = 0. Similarly, if you tried n = 2, you should get 1^2 = 1, and so on. It appears you already wrote the answer when you wrote "Mark Scheme".

All of this only applies to sequence A.

side note: n is some positive whole number.

8 0

3 years ago