Answer:
m∠R is 72°
Step-by-step explanation:
In the given figure
∵ ΔPQR ≅ ΔUVW
→ From congruency
∵ m∠P = m∠U
∵ m∠Q = m∠V
∴ m∠R = m∠W
∵ m∠R = (10x - 18)°
∵ m∠W = 8x°
∵ m∠R = m∠W
→ Equate their measures
∴ 10x - 18 = 8x
→ Add 18 to both sides
∵ 10x - 18 + 18 = 8x + 18
∴ 10x = 8x + 18
→ Subtract 8x from both sides
∴ 10x - 8x = 8x - 8x + 18
∴ 2x = 18
→ Divide both sides by 2 to find x
∴ x = 9
→ Substitute the value of x in the m∠R
∵ m∠R = 10(9) - 18
∴ m∠R = 90 - 18
∴ m∠R = 72°
∴ m∠R is 72°
Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense
Answer:
The coordinates of H′ are (-2,0).
Step-by-step explanation:
It is given that square EFGH stretches vertically by a factor of 2.5 with respect to the x-axis to create rectangle E′F′G′H′.
If a figure stretches vertically by a factor of 2.5 with respect to the x-axis, then the x-coordinates remains same and the points which lie on the axis are also remains the same after stretch.
It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.
Therefore the coordinates of H′ are (-2,0).
We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation 
.
To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate 
and solve for t as:
Now we will switch sides:
Let us take natural log on both sides of equation.
Using natural log property 
, we will get:
Therefore, it will take 
years for area of the glacier to decrease to 15 square kilo-meters.
Answer: x = -3
set them equal to each other and reverse pemdas as shown in my image
