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MaRussiya [10]
2 years ago
7

Four friends are sharing $95. they keep a record of what they do. First they splilt up the $10 bills

Mathematics
1 answer:
Ainat [17]2 years ago
8 0

Answer:

Now they have $55 in total left

Step-by-step explanation:

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With complete solution please I need Thanks​
Liula [17]

Answer:

14

Step-by-step explanation:

We can make this and equation

x • y = 1260

x = 3y +48

Our equation is

(3y +48)y = 1260

We get y = 14

6 0
2 years ago
*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
Solve for x: 3(x + 1) = −2(x − 1) − 4<br><br> 1<br><br> −1<br><br> −5<br><br> −25
LekaFEV [45]

Answer:

x = - 1

Step-by-step explanation:

3(x + 1) = - 2(x - 1) - 4 ←  distribute parenthesis on both sides

3x + 3 = - 2x + 2 - 4

3x + 3 = - 2x - 2 ( add 2x to both sides )

5x + 3 = - 2 ( subtract 3 from both sides )

5x = - 5 ( divide both sides by 5 )

x = - 1

7 0
2 years ago
Write an expression for " the quotient of q and 9​
Dmitry_Shevchenko [17]

Answer:

q/9

Step-by-step explanation:

The quotient is an number or variable that is the product of division. My answer may be reversed or wrong, but it should be close to the correct one.

8 0
3 years ago
Which point lies on the graph of the function shown below y=-x^2+5x-3
Andrei [34K]

Answer:

C: (2,3)

Step-by-step explanation:

to solve this algebraically just plug in the x and y values of the points and see if they are true, but here is the graph to juse show you

4 0
3 years ago
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