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2 years ago

7(6+d)=49 Solve for d. A:d=7 B:d=-1 C:d=-7 D:d=1

Mathematics

1 answer:

Elan Coil [88]2 years ago

3 0

Answer: d = 1

Step-by-step explanation:

First distribute the 7 to each term of (6 + d) = 42 + 7d = 49 now subtract 42 from both sides which = 7d = 7. Divide by 7 = 7d/7 = 7/7 = d = 1

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Answer:

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Question 1

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Question 2:

Following the steps as in question 1

${ \rm{y = {x}^{2} - 4}} \\ \\{ \rm{2x - 4 = {x}^{2} - 4}} \\ \\ { \rm{ {x}^{2} = 2x }} \\ \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}$

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Step-by-step explanation:

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Step-by-step explanation:

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