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lora16 [44]
3 years ago
14

a charge Q exerts a 2.4 N force on another charge q.If the distance between the charges is doubled,what is the magnitude of the

force exerted on Q by q ?
Physics
1 answer:
GrogVix [38]3 years ago
6 0
Heyyyyyyyyyy how is your day goingggg luvvvv
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What is the kinetic energy of a 0.5 kg soccer ball that’s traveling at a speed of 3m/s
Julli [10]

Answer:

K.E is 2.25 J

Explanation:

Data :

Mass = m = 0.5 kg

Velocity = v = 3 m/s

Formula for K.E

K.E = 1/2mv²

Put values

K.E = 1/2(0.5)(3)² = 2.25 J

5 0
3 years ago
Read 2 more answers
A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car
kogti [31]

Answer:

t_1 = \frac{v_i}{a_i}

t_2 = \frac{v_i}{a_i}

Δd = v_it_1 = v_i^2/a_i

Explanation:

As v(t) = v_i + at, when the car is making full stop, v(t_1) = 0 . a = -a_i . Therefore,

0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}

Apply the same formula above, with v(t_2) = v_i and a = a_i, and the car is starting from 0 speed,  we have

v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}

As s(t) = vt + \frac{at^2}{2}. After t = t_1 + t_2, the car would have traveled a distance of

s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}

Hence s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}

As t_1 = t_2 we can simplify s(t) = v_it_1

After t time, the train would have traveled a distance of s(t) = v_i(t_1 + t_2) = 2v_it_1

Therefore, Δd would be 2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i

8 0
3 years ago
Starting from rest, a 75.0-kg snowboarder slides straight down a 115-m slope in 6.6 s. If the slope is a 35°
Likurg_2 [28]

The acceleration of the snowboarder is 5.6 m/s^2 down along the incline

Explanation:

To find the acceleration of the snowboard, we have to analyze the forces acting along the direction parallel to the incline.

There is only one force acting in this direction, and it is the component of the weight parallel to the incline, given by

mg sin \theta

where

m = 75.0 kg is the mass of the man

g=9.8 m/s^2 is the acceleration of gravity

\theta=35^{\circ} is the angle of the incline

Substituting, we find that the net force along the incline is:

F=(75.0)(9.8)(sin 35^{\circ})=421.6 N

According to Newton's second law, the net force on the snowboard is equal to the product between his mass and his acceleration:

F=ma

where a is the acceleration. Therefore, solving for a, we find

a=\frac{F}{m}=\frac{421.6}{75}=5.6 m/s^2

And the direction of this acceleration is down along the incline.

Learn more about acceleration and Newton's second law:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

8 0
3 years ago
A trumpet player, using her ear, hears 5 beats per second when she plays a note on her trumpet and simultaneously sounds a 440 H
german

<h2>Frequency of trumpet wire = 445 Hz</h2>

Explanation:

The given  frequency of tuning fork is 440 Hz . It produces 5 beats with trumpet wire . That means , the frequency of wire can be 440 ± 5

It can be either 445 or 435

Now the length of wire is increased , by which its frequency decreases . Because frequency is inversely proportional to length of wire .

If we decrease the frequency in 435 , the difference between tuning fork frequency and wire frequency will become greater than 5 even . So it cannot produce 3 beats with it .

If we decrease frequency from 445 , it can become 443 Hz . It gives 3 beat with the tuning fork as given .

Thus the initial frequency of wire is 445 Hz

4 0
3 years ago
A 2-kg block sliding at 4.5m's north hits a wall and rebounds at 3.2 m s south What is the object's change in momentum?​
ZanzabumX [31]

Answer:

2.6kgm/s

Explanation:

Momentum is the product of mass of an object and its velocity

Change in momentum = mass × change in velocity

Change in momentum = m∆v

Given

Mass m =2kg

Change in velocity ∆v = 4.5-3.2

∆v = 1.3m/s

Change in momentum = 2×1.3

Change in momentum = 2.6kgm/s

Hence the object change in momentum is 2.6kgm/s

6 0
3 years ago
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