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Damm [24]
3 years ago
5

A trumpet player, using her ear, hears 5 beats per second when she plays a note on her trumpet and simultaneously sounds a 440 H

z tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. What was the trumpet players' initial frequency?
Physics
1 answer:
german3 years ago
4 0

<h2>Frequency of trumpet wire = 445 Hz</h2>

Explanation:

The given  frequency of tuning fork is 440 Hz . It produces 5 beats with trumpet wire . That means , the frequency of wire can be 440 ± 5

It can be either 445 or 435

Now the length of wire is increased , by which its frequency decreases . Because frequency is inversely proportional to length of wire .

If we decrease the frequency in 435 , the difference between tuning fork frequency and wire frequency will become greater than 5 even . So it cannot produce 3 beats with it .

If we decrease frequency from 445 , it can become 443 Hz . It gives 3 beat with the tuning fork as given .

Thus the initial frequency of wire is 445 Hz

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Answer: The frequency heard will be f = 275.675Hz

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The formula to calculate the Doppler effect is as follows

f = (\frac{c}{c+Vs}) · f₀

f is the observed frequency;

c is the speed of sound;

Vs is velocity of the source;

f₀ is the emitted frequency of source;

Substituting and calculating,

f = \frac{340}{340+30} · 300

f = 275.675 Hz

Thus, the frequency heard by the police officer is 275.675Hz.

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4 years ago
A velocity selector is built with a magnetic field of magnitude 5.2 T and an electric field of strength 4.6 × 10 ^ 4 N/C. The di
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Explanation :

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The directions of the two fields are perpendicular to each other. Hence the force due to each field will equate each other.

Electrostatic force, F =qE.........(1)

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From equation (1) and (2)

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v=\dfrac{E}{B}

v=\dfrac{4.6\times 10^4\ N/C}{5.2\ T}

v=0.88\times 10^4\ m/s

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