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Damm [24]
3 years ago
5

A trumpet player, using her ear, hears 5 beats per second when she plays a note on her trumpet and simultaneously sounds a 440 H

z tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. What was the trumpet players' initial frequency?
Physics
1 answer:
german3 years ago
4 0

<h2>Frequency of trumpet wire = 445 Hz</h2>

Explanation:

The given  frequency of tuning fork is 440 Hz . It produces 5 beats with trumpet wire . That means , the frequency of wire can be 440 ± 5

It can be either 445 or 435

Now the length of wire is increased , by which its frequency decreases . Because frequency is inversely proportional to length of wire .

If we decrease the frequency in 435 , the difference between tuning fork frequency and wire frequency will become greater than 5 even . So it cannot produce 3 beats with it .

If we decrease frequency from 445 , it can become 443 Hz . It gives 3 beat with the tuning fork as given .

Thus the initial frequency of wire is 445 Hz

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A(n) 930 N crate is being pushed across a level floor by a force of 400 N at an angle of 20◦ above the horizontal. The coefficie
Nana76 [90]

Answer:

The magnitude of the acceleration of the box is 2.291\,\frac{m}{s^{2}}.

Explanation:

The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:

\Sigma F_{x} = P\cdot \cos 20^{\circ} - \mu_{k}\cdot N = \left(\frac{W}{g}\right)\cdot a

\Sigma F_{y} = P\cdot \sin 20^{\circ} + N - W = 0

From second equation of equilibrium we find an expression for the normal force and find the respective value:

N = W - P \cdot \sin 20^{\circ}

N = 930\,N - 400\cdot \sin 20^{\circ}\,N

N = 793.192\,N

Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:

a = \frac{P\cdot \cos 20^{\circ}-\mu_{k}\cdot N}{\frac{W}{g} }

a = \frac{400\cdot \cos 20^{\circ}\,N-0.20\cdot (793.192\,N)}{\frac{930\,N}{9.807\,\frac{m}{s^{2}} } }

a = 2.291\,\frac{m}{s^{2}}

The magnitude of the acceleration of the box is 2.291\,\frac{m}{s^{2}}.

3 0
3 years ago
A medicine ball has a mass of 5 kg and is thrown with a speed of 2 m/s. what is its kinetic energy?
Fantom [35]
The kinetic energy of the ball is given by:
K= \frac{1}{2}mv^2
where m=5 kg is the mass of the ball and v=2 m/s is its speed. Substituting these numbers, we find the kinetic energy:
K= \frac{1}{2} (5kg)(2m/s)^2=10 J
7 0
4 years ago
A 37.5 kg box initially at rest is pushed 4.05 m along a rough, horizontal floor with a constant applied horizontal force of 150
vodomira [7]

Answer:

a) 607.5 J

b) 160.531875 J

c)  0 J

d)  0 J

e) 2.925 m\s

Explanation:

The given data :-

  • Mass of the box ( m ) = 37.5 kg.
  • Displacement made by box ( x ) = 4.05 m.
  • Horizontal force ( F ) = 150 N.
  • The co-efficient of friction between box and floor ( μ ) = 0.3
  • Gravitational force ( N ) = m × g = 37.5 × 9.81 = 367.875

Solution:-

a) The work done by applied force ( W )

W = force applied × displacement = 150 × 4.05 = 607.5 J

b)  The increase in internal energy in the box-floor system due to friction.

Frictional force ( f ) = μ × N = 0.3 × 367.875 = 110.3625 N

Change in internal energy = change in kinetic energy.

ΔU = ( K.E )₂ - ( K.E )₁

Since the initial velocity is zero so the  ( K.E )₁ = 0  

ΔU = ( K.E )₂ = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

c) The work done by the normal force .

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

d)  The work done by the gravitational force.

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

e) The change in kinetic energy of the box

( K.E )₂ - ( K.E )₁ = ( K.E )₂ - 0 = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

f) The final speed of the box

( K.E )₂ = 160.531875 J = 0.5 × 37.5 × v²

v² = 8.56

v = 2.925 m\s.

5 0
3 years ago
A camcorder has a power rating of 13 watts. If the output voltage from its battery is 6 volts, what current does it use?
leva [86]

Power = (voltage) x (current)

13 watts = (6 volts) x (current)

Divide each side by (6 volts):

Current = (13 watts) / (6 volts)

Current = (13/6) Amperes

<em>Current = 2.17 Amperes</em>

5 0
4 years ago
Multiply the following numbers, using scientific notation and the correct amount of significant digits. 1.003 m⋅3.09 = _____ 3.0
lozanna [386]

Answer

correct answer is 3.10

Explanation:

in this question we have to multiply  two numbers 1.003 and 3.09.

1.003 has 4 significant digits and 3.09 has 3 significant digits so answer must have 3 significant digits.

1.003\times 3.09=3.09927

1.003\times 3.09=3.10              


Hope it will help you

3 0
3 years ago
Read 2 more answers
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