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Lostsunrise [7]
3 years ago
11

A model rocket is launched at an angle of 70° above the x axis, with an initial velocity of 40 m/s. How high will the rocket be

5 seconds after launch?
A. 36.8 m
B. 65.4 m
C. 84.9 m
D. 122.5 m
Physics
2 answers:
s2008m [1.1K]3 years ago
7 0

Answer:

65.4 is your answer

Explanation:

Ilia_Sergeevich [38]3 years ago
4 0

Option (B) is correct.

using kinematic equation

h= V sin\theta t+ \frac{1}{2}gt^2

h= height of rocket

V= initial velocity= 40 m/s

t= time= 5 s

g= -9.8 m/s²

h=40 sin70 (5)+1/2 (-9.8)(5)²

h=65.4 m

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