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Lostsunrise [7]
3 years ago
11

A model rocket is launched at an angle of 70° above the x axis, with an initial velocity of 40 m/s. How high will the rocket be

5 seconds after launch?
A. 36.8 m
B. 65.4 m
C. 84.9 m
D. 122.5 m
Physics
2 answers:
s2008m [1.1K]3 years ago
7 0

Answer:

65.4 is your answer

Explanation:

Ilia_Sergeevich [38]3 years ago
4 0

Option (B) is correct.

using kinematic equation

h= V sin\theta t+ \frac{1}{2}gt^2

h= height of rocket

V= initial velocity= 40 m/s

t= time= 5 s

g= -9.8 m/s²

h=40 sin70 (5)+1/2 (-9.8)(5)²

h=65.4 m

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mars1129 [50]
<h3><u>Answer;</u></h3>

= 20.436 seconds

<h3><u>Explanation;</u></h3>

Speed = Distance × time

Therefore;

Time = Distance/speed

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Time = 7.50/0.367

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7 0
3 years ago
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Answer:

t = 2.01 s

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Explanation:

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  • Time (t) = ?
  • Final Velocity (Vf) = ?

==================================================================

Time

Use formula:

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Replace:

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Everything inside the root is solved first. So, we solve the multiplication of the numerator:

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==================================================================

Final Velocity

use formula:

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Replace:

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==================================================================

How long does it take to reach the ground?

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How fast does it hit the ground?

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7 0
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3 0
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ira [324]

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8 0
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