Answer:
N1 / N2 = 1.0016
Explanation:
The apparent weight of the student is the value that a balance would have this corresponds in this case to the normal of the student. Let's write Newton's second law in the lower and upper part of the loop
For lower rotating wheel
N1 - W = m a
a = v² / r
N1 = W + v² / r
The relationship between linear and angular velocity is
v = w r
As the wheel rotates at a constant speed, we can use angular kinematics
w = θ / t
θ = 3 rev (2π rad / 1rev) = 6π rad
w = 6π / 150
w = 0.04π rad / s = 0.1257 rad / sec
calculate
N1 = mg + w² r
N1 = 55 9.8 + 0.1257² 27
N1 = 539 + 0.4267
N1 = 539.426 N
Now we perform the same calculation for the top
-N2 - W = -m a
N2 = -W + ma
N2 = 539 - 0.4267
N2 = 538.5733 N
The relationship between the weight at the bottom and top is
N1 / N2 = 539.4267 / 538.5733
N1 / N2 = 1.0016
False its really its not true
To solve this question you need to find the time span of the ski jumper before he lands
thus
25 = 1/2*10*t^2
50/10 = t^2
t = 2.23 seconds
and the distance is given 135m
speed = distance/time
= 135/2.23
= 60.5 m/s
Answer:
The energy lost is 0.333156518 J.
Explanation:
The given mass of the pendulum = 0.259 kg
Length = 0.97 m
Displaced at an angle of = 31.4 degrees
Maximum angle of swing = 10 degrees
Initial potential energy = mgh
Initial potential energy = 0.259 × 9.8 × (1 – cos31.4)
= 0.259 × 9.8 × ( 1- 0.853551)
= 0.371716852 J
Final potential energy = mgh
Final potential energy = 0.259 × 9.8 × (1 – cos10)
= 0.259 × 9.8 × (1 – 0.984808)
= 0.0385603344 J
The lost energy = Initial potential energy - Final potential energy
= 0.371716852 J - 0.0385603344 J
= 0.333156518 J
0.45 <span>f we use 0.45 moles of KCl completely, we will produce the same amount\of AgCl. The fact about AgF Is irrelevant! </span>