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3 years ago

Karen wants to string lights around the edge of her deck. The shape and dimensions of her deck are shown in the diagram

Mathematics

1 answer:

Marianna [84]3 years ago

8 0

She would need 70 feet of lights

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How do you figure this out?

podryga [215]

$2x^2-4x-6=0\\ x^2-2x-3=0\\ x^2+x-3x-3=0\\ x(x+1)-3(x+1)=0\\ (x-3)(x+1)=0\\ x=3 \vee x=-1$

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4 years ago

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Larry works across town, 24 miles from his home. On a map with a scale of 2 inches equals 3 miles, what is the distance between

Paladinen [302]

Answer:

Step-by-step explanation:

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3 years ago

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ASAP!!! Please answer the FIRST TWO and LAST TWO, ignore the answer asking for a graph.

ch4aika [34]

Answer:

Step-by-step explanation:

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3 years ago

4/r=5/7solve for r. Help pls

antiseptic1488 [7]

Hello!

You first cross multiply

4 * 7 = 28

5 * r = 5 * r

r * 5 = 28

Divide both sides by 5

r = 28/5 = 5.6

The answer is 28/5 or 5.6

Hope this helps!

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3 years ago

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F(x)=1/2×+6 plz helpppppppppp

FromTheMoon [43]

Answer:

The solution set can be given as:

$\{x|x\ \epsilon\ R,x\neq -3\}$

Step-by-step explanation:

Given function:

$f(x)=\frac{1}{2x+6}$

To find the domain of the function in set notation.

Solution:

For the function $f(x)$ to exist the denominator must be ≠ 0

We have the denominator $(2x+6)$ which cannot be = 0.

Thus, we can find the domain of the function using the above relation.

The function $f(x)$ will not exist when:

$2x+6=0$

Solving for $x$

Subtracting both sides by 6.

$2x+6-6=0-6$

$2x=-6$

Dividing both sides by 2.

$\frac{2x}{2}=\frac{-6}{2}$

∴ $x=-3$

Thus, the function will not exist at $x=-3$ . This means it has all real number solutions except -3.

The solution set can be given as:

$\{x|x\ \epsilon\ R,x\neq -3\}$

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4 years ago