First, we need to know what the slope is of a line that would be perpendicular to a line with a slope of -5/6. To find this, we take the reciprocal and multiply it by -1. Therefore, the line we are looking for needs to have a slope of 6/5.

Based on the fact that the slope is positive, we can eliminate lines PQ and JK as they have a negative slope. This leaves us with lines LM and NO.

To find out whether or not it is between LM and NO, you could eyeball it by looking at the graph and simply counting which might be faster if you understand how to do that (rise/run), or you can use the pair of coordinates given to you on each line to calculate for slope.

Line LM - $\frac{-3-3}{-5-0}=\frac{-6}{-5}=\frac{6}{5}$

Line NO - $\frac{-5-0}{-6-0}=\frac{-5}{-6}=\frac{5}{6}$

Based on this, we know that line LM is perpendicular to a line that has a slope of -5/6.

<em>If you need help on calculating slope from two points, I'd suggest watching this video: </em><u>https://www.brightstorm.com/math/algebra/linear-equations-and-their-graphs/finding-the-slope-of-a-line-from-2-points-problem-1/#:~:text=Use%20the%20slope%20formula%20to,second%20points%20are%20x2%2C%20y2.</u>

7 0

2 years ago

Show me this problem solved on paper?

Genrish500 [490]

Answer:

345 ×12 = 4140

Step-by-step explanation:

$345 * 2 = 690\\345 * 10 = 3450\\690 + 3450 = 4140.$

hope this helps

7 0

3 years ago

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