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Irina18 [472]
4 years ago
10

F(x) = 5x and g(x) = x + 11.

Mathematics
2 answers:
aleksklad [387]4 years ago
5 0

Answer:

5x^2 + 55x

Step-by-step explanation:

Let's review f(x)g(x) simply means you multiply both functions together.

So,

(5x)(x+11)

5x * x = 5x^2

5x * 11 = 55x

Hence, the answer is 5x^2 + 55x

ratelena [41]4 years ago
3 0

Answer:

C

Step-by-step explanation:

f(x) × g(x)

= 5x(x + 11) = 5x² + 55x, thus

h(x) = 5x² + 55x → C

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Find the area of rectangle, where length is 15 cm and breadth is 7 cm.​
Varvara68 [4.7K]

Question :-

  • Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .

Answer :-

  • Area of Rectangle is 105 cm² .

\rule {195pt} {2pt}

Diagram :-

\sf{15 \: cm} \\ \quad \quad  \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\   \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\  \\  \\ \end{array}}  \:  \:  \sf {7 \: cm}\end{gathered}\end{gathered}

\rule {195pt} {2pt}

Solution :-

\quad \quad » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.

For calculating the Area of Rectangle , we will use the Formula :-

  • \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth}

Therefore , by Substituting the given values in the above Formula :-

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7}

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105}

Hence :-

  • Area of Rectangle = 105 cm² .

\underline {\rule {195pt} {4pt}}

Additional Information :-

\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \:  \: More \: Formulas \:  \:  \dag}}}} \\  \\  \\  \footnotesize \bigstar  \:  \bf{Area \: _{Square} = Side \times Side}  \\  \\  \\   \footnotesize\bigstar  \:  \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Triangle} =  \frac{1}{2} \times Base \times Height } \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Parallelogram} = Base \times Height} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Trapezium} =  \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}

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3 years ago
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