ASAPPPPP

kow [346]

$The\ surface\ area:A_s=2B+(S_1+S_2+S_3)\cdot H\\B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\S_1=5yd;\ S_2=12yd;\ S_3=13yd;\ h=8yd\\\\therefore\\\\A_s=2\cdot30+(5+12+13)\cdot8=60+30\cdot8=60+240=\boxed{300\ (yd^2)}$ $Volume\ of\ the\ prism:V=B\cdot H\\\\B\ (base)\ it's\ a\ right\ triangle:B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\H=8yd\\\\therefore\\\\V=30\cdot8=\boxed{240\ (yd^2)}\leftarrow\boxed{C}$

8 0

3 years ago

Read 2 more answers

the British Thermal Unit(BTU) is a unit of energy used globally in air conditioning industries. the number of BTUs needed to coo

7nadin3 [17]

Answer:

32.5 m^2

Step-by-step explanation:

B = 377lw

I will use L for length instead of l.

B = 12,252.5 BTU

w = 5 m

First, we find the length.

12,252.5 = 377(L)(5)

12,252.5 = 1885L

L = 6.5

The length is 6.5 m. The width is 5 m.

A = LW = (6.5 m)(5 m) = 32.5 m^2

4 0

3 years ago

You are working for a company that designs boxes, bottles and other containers. You are currently working on a design for a milk

ra1l [238]

Volume is a measure of the quantity of substance a given object can contain. The required answers are:

1.1 The volume of each milk carton is 360 $cm^{3}$ .

1.2 The area of cardboard required to make a single milk carton is 332.6 $cm^{2}$ .

1.3 Each carton can hold 0.36 liters of milk.

1.4 The cost of filling the 200 cartons is R 86.40.

The volume of a given shape is the amount of substance that it can contain in a 3-dimensional plane. Examples of shapes with volume include cubes, cuboids, spheres, etc.

The area of a given shape is the amount of space that it would cover on a 2-dimensional plane. Examples of shapes to be considered when dealing with the area include triangle, square, rectangle, trapezium, etc.

The box to be considered in the question is a cuboid. So that;

Volume of cuboid = length x width x height

Thus,

1.1 The volume of each milk carton = length x width x height

= 6 x 6 x 10

= 360

The volume of each milk carton is 360 $cm^{3}$ .

1.2 The total area of cardboard required to make a single milk carton can be determined as follows:

i. Area of the rectangular surface = length x width

= 6 x 10

= 60

Total area of the rectangular surfaces = 4 x 60

= 240 $cm^{2}$

ii. Area of the square surface = side x side = s²

= 6 x 6

Area of the square surface = 36 $cm^{2}$

iii. There are four semicircular surfaces, this implies a total of 2 circles.

Area of a circle = $\pi r^{2}$

where r is the radius of the circle.

Total area of the semicircular surfaces = 2 $\pi r^{2}$

= 2 x $\frac{22}{7}$ x $(3)^{2}$

= 56.57

Total area of the semicircular surfaces = 56.6 $cm^{2}$

Therefore, total area of cardboard required = 240 + 36 + 56.6

= 332.6 $cm^{2}$

The area of cardboard required to make a single milk carton is 332.6 $cm^{2}$ .

1.3 Since,

1 $cm^{3}$ = 0.001 Liter

Then,

360 $cm^{3}$ = x

x = 360 x 0.001

= 0.36 Liters

Thus each carton can hold 0.36 liters of milk.

1.4 total cartons = 200

Total volume of milk required = 200 x 0.36

= 72 litres

But, 1 kiloliter costs R1 200. Thus

Total volume in kiloliters = $\frac{72}{1000}$

= 0.072 kiloliters

The cost of filling the 200 cartons = R1200 x 0.072

= R 86.40

The cost of filling the 200 cartons is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

#SPJ1

4 0

2 years ago

A suitcase measures 21 inches by 16 inches. What is the length of the diagonal of the suitcase to the nearest tenth of an inch?

kap26 [50]

Answer:

Step-by-step explanation:

we have a rectangle that measure 21 inches by 16 inches

to find the rectangle(which is the hypotenuse) we will use Pythagorean theorem

c^=a^2+b^2

c^=21^2+16^2=697

c= $\sqrt697}$ =26.40 which rounded to the nearest tenth =26

7 0

2 years ago

can y’all please help me

Alexxx [7]

Answer:

15. d(1,3) e(4,4) g(1,-1) f(4,-2)

16. e(2,-1) f(4,-1) g(2,-3) h(4,-5)

Step-by-step explanation:

These are the coordinates to each point (x,y)

I hope this helps!!

3 0

2 years ago