Answer:
0.2 ; 100 ; 4.84
Step-by-step explanation:
Given that the probability of each of the 5 groups is the same :
Sum of probability = 1
Hence, Probability of each group = 1 / number of groups = 1 / 5 = 0.2
Expected number for each interval for a sample of 500 : ; X = 500
E(X) = X * P(x) = 500 * 0.2 = 100
Goodness of fit (X²) :
X² = Σ(X - E)² ÷ E
Groups :
113, 95, 108, 99, and 85
X : 113 ____ 95 ____ 108 ____ 99 _____ 85
(113 - 100)^2 / 100 = 1.69
(95 - 100)^2 / 100 = 0.25
(108 - 100)^2 / 100 = 0.64
(99 - 100)^2 / 100 = 0.01
(85 - 100)^2 / 100 = 2.25
(1.69 + 0.25 + 0.64 + 0.01 + 2.25) = 4.84
∆x = (4--4)=8
∆y = (7--3)= 10
Step-by-step explanation:
distance is given by;
d² = (∆y)²+ (∆x)²
d = √((∆y)²+ (∆x)²)
d = √((4+4)² + (7+3)²)
d = √((8²) + (10²))
d = √(64+100)
d = √164
<em><u>d =12.806 units</u></em>
Answer:
No solution
Step-by-step explanation:
-3--4 =
-3 + 4 =
1
(Two negatives make a positive)
Answer: 1
