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maksim [4K]
3 years ago
13

Can ace and expert help me

Mathematics
2 answers:
Sphinxa [80]3 years ago
6 0

Answer:

D

Step-by-step explanation:

repeat

JulijaS [17]3 years ago
5 0
<h2><u>Question :-</u></h2>

In which number does 7 represent 10 times the value that it represents in 167 300.

<h3>____________________</h3>

<h2><u>Solution :-</u></h2>

<h3><u>Given Information :-</u></h3>

  • <u>Number ➢</u> 167 300

<h3><u>To Find :-</u></h3>

  • In which number does 7 represent 10 times the value that it represents in 167 300.

  • 215,007
  • 392,070
  • 450,700
  • 572,000
  • 791,000

<h3><u>Calculation :-</u></h3>

In the given number, we can observe that, the face value of digit 7 is on 'Thousands place'. If multiply 7, 10 times, the face value of digit 7 will shift to it's Left Side by 1 digit, since, this condition is seen in the 4th option provided, hence, option 4. 572,000 is the correct answer.

<h3>____________________</h3>

<h2><u>Final Answer :-</u></h2>

Option 4. 572,000 is the correct answer

<h3>___________________</h3>
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              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
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Step-by-step explanation:

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Step-by-step explanation:

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