What is 8.154 rounded to 2 decimal places?" is the same as asking, "What is 8.154 rounded to two decimal points?" or "How to round 8.154 to two decimal places."
The main point is that you want to round 8.154 to two digits or places after the decimal point. Thus, we want to eliminate the last digit in 8.154. To eliminate the last digit in 8.154, we use the following Two Decimal Places Rules to get the answer:
Two Decimal Places Rule #1: If the last digit in 8.154 is less than 5, then remove the last digit.
Two Decimal Places Rule #2: If the last digit in 8.154 is 5 or more and the second to the last digit in 8.154 is less than 9, then remove the last digit and add 1 to the second to the last digit.
What is the height of the cylinder??
G(x)=9
f(g(x))= 9(2)+9+2=29
![\sf{14(\sqrt[3]{x}) }](https://tex.z-dn.net/?f=%5Csf%7B14%28%5Csqrt%5B3%5D%7Bx%7D%29%20%7D)
Step-by-step explanation:
![5(\sqrt[3]{x})+9(\sqrt[3]{x})\\\\(5+9)(\sqrt[3]{x})\\\\14(\sqrt[3]{x})](https://tex.z-dn.net/?f=5%28%5Csqrt%5B3%5D%7Bx%7D%29%2B9%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C%285%2B9%29%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C14%28%5Csqrt%5B3%5D%7Bx%7D%29)
Answer:
Step-by-step explanation:
In standard form this could be rewritten as | b - 0 | > 6, which in words, says,
"b is greater than 6 units away from 0 on a number line". If b is greater than 6 units away, both positive 6 and negative 6 are 6 units away from 0. Because the values we need are greater than 6 units away from 0, we are starting at both 6 and -6 and moving away from 0.
The "greater than" symbol indicates that this is a disjunction so the word "or" is used as opposed to in a conjunction where the word "and" is used.
Therefore, our solutions are
b < -6 or b > 6, the 3rd choice down
