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3 years ago

Find the y intercepts and x for 11, 12

Mathematics

2 answers:

azamat3 years ago

8 0

11.

x= 5 and y= -6

12. x= -4 and y= -5

Ira Lisetskai [31]3 years ago

4 0

Answer:

11.

y-int: 3

x-int: -6

slope: 1/2

12.

y-int: -5

x-int: -4

slope: 1

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RST with vertices R(–2, 3), S(1, 2), and T(2, –1) is rotated 270° counterclockwise about the origin.

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3 years ago

9(n+3)=7n-3 Help Me Find "X"

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9(n+3)=7n-3

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3 years ago

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If the numerator of a fraction is increased by six, the value of the fraction will increase by one. If the denominator of the or

Alchen [17]

Answer:

$\dfrac{7}{6}$

Step-by-step explanation:

Let $\dfrac{a}{b}$ be the original fraction.

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. Hence,

$\dfrac{a+6}{b}=\dfrac{a}{b}+1$

If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

$\dfrac{a}{b+36}=\dfrac{a}{b}-1$

Add these two equalities:

$\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36$

Substitute it into the first equation:

$\dfrac{a+6}{6a-36}=\dfrac{a}{6a-36}+1\\ \\\dfrac{a+6}{6(a-6)}=\dfrac{a}{6(a-6)}+1\\ \\a+6=a+6(a-6)\\ \\a+6=a+6a-36\\ \\6a=6+36\\ \\6a=42\\ \\a=7\\ \\b=6\cdot 7-36=42-36=6$

Thus, the initial fraction was

$\dfrac{7}{6}$

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4 years ago