The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
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A really out of focus picture, but I think this might be what you want.
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Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is

Here [ a, b ] = [ - 1, 6 ] and from the graph
f(b) = f(6) = 0
f(a) = f(- 1) = 0, thus
average rate of change =
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The three angles of a triangle should equal 180 so add 52+34 which equals 86.Then subtract 86 from 180 to get the third angles measure which is 94 so the answer is 94.