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3 years ago

Whats the answer to question b???? please help

Mathematics

1 answer:

irinina [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Yes they would.

2x+3x+x+90=360

6x=270

x=45

Angle A=2x

Angle A=2(45)=90 degrees

So both AD and BC are vertical lines which are parallel to each other.

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A company advertises that its cans of caviar each contain 100 g of their product. A consumer advocacy group doubts this claim, a

Blizzard [7]

Answer:

The value of the test statistic is -3.14.

Step-by-step explanation:

Test statistic:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected value, $\sigma$ is the standard deviation and n is the size of the sample.

A company advertises that its cans of caviar each contain 100 g of their product.

This means that $\mu = 100$

They calculate a sample mean weight of 99 g and a sample standard deviation of 0.9 g. Sample of 8 cans.

This means that $X = 99, \sigma = 0.9, n = 8$

So the test statistic will be given by:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{99 - 100}{\frac{0.9}{\sqrt{8}}}$

$t = -3.14$

The value of the test statistic is -3.14.

8 0

3 years ago

Thanks!! got a 100% on the test bc of brain.ly

Lorico [155]

Your welcome ig brainly helps everyone in need of help

5 0

3 years ago

Read 2 more answers

In the circle below, DB = 22 cm, and m<DBC = 60°. Find BC. Ignore my handwriting.

Karo-lina-s [1.5K]

Answer:

$BC=11\ cm$

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

$m\angle DBC=\frac{1}{2}[arc\ DC]$

substitute the values

$60\°=\frac{1}{2}[arc\ DC]$

$120\°=arc\ DC$

$arc\ DC=120\°$

step 2

Find the measure of arc BC

we know that

$arc\ DC+arc\ BC=180\°$ ----> because the diameter BD divide the circle into two equal parts

$120\°+arc\ BC=180\°$

$arc\ BC=180\°-120\°=60\°$

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

$m\angle BDC=\frac{1}{2}[arc\ BC]$

substitute the values

$m\angle BDC=\frac{1}{2}[60\°]$

$m\angle BDC=30\°$

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

$sin(\angle BDC)=BC/BD$

$BC=(BD)sin(\angle BDC)$

substitute the values

$BC=(22)sin(30\°)=11\ cm$

6 0

3 years ago

PLEASE HELP ASAP I’LL MARK BRAINLIEST Find the area of the figure.

Sonbull [250]

Area of a semicircle is 1/2* πr^2
Area of a square is s^2

Square’s area: 4mm^2

The radius is 3mm
Plug into the equation

1/2* π(3^2)
1/2* π(9)

We can use 3.14 as an estimate of pi

1/2*28.26

14.13mm^2

Now just add them both

Total area 18.13mm^2

4 0

3 years ago

Plz help and thanks so much for it

kirza4 [7]

B+c+(c-b)+(b-c). That is your expression. b 11 c 16

First, let's convert the variables to real numbers: 11+16+(16-11)+(11-16)
Now, let's solve that equation. 11+16+5+(-5)
5+(-5) cancels out, so all we have left is: 27
That is your perimeter.

7 0

3 years ago