C=x+9, c+x=99, c=99-x
So we have two equations equal to c, c=x+9 and c=99-x, since c=c:
x+9=99-x
2x+9=99
2x=90
x=45, and since c=x+9, c=54
So Charlie weighs 54 kg and his brother weighs 45 kg.
Step-by-step explanation:
y=(-x^2)+12x-20
=(-(3)^2)+12(3)-20
=(-9)+36-20
=16-9=7
y=7
I hope it helped you
U probably need to add in a picture
Ok since the athlete an equal distance of 2 days a week and he runs a total of 11 miles in 5 days you will need to think back so before he had 11 miles done next weak he had a total of 19 miles so you will start at 11 then count up to 19.
Use a number line to show how many days it took for the athlete to get 19 miles.
Then once you do the number line count the lumps and that’s how many days it took for the athlete to get 19 miles.
Hope this helped.
<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
