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3 years ago

(-1,-2) and (2,13) what is the slope

Mathematics

1 answer:

masya89 [10]3 years ago

6 0

Answer:

slope is 5

Step-by-step explanation:

first you subtract the second y minus the first y then you subtract the second x minus the first x and then u divide the result of y over the result of x :)

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3 years ago

Delia, Edwin and Freya share some money in the ratio 5 : 7 : 8. Freya’s share is £1600. How much money did they share?

FrozenT [24]

Answer:

To find how much money they shared first find the total parts

Which is

5 + 7 + 8 = 20

Deila's share is

5 /20 × £1600

= 1/4 × £1600 = £ 400

Edwin's share is

7/ 20 ×£1600 = £560

Freya's share is

8/20 × £1600

= 2/5 × £1600 = £640

Hope this helps you

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME I SUCK AT MATH

ICE Princess25 [194]

ANSWER:
A. y= -4x - 4

EXPLANATION:
y2-y1
——— This is used to find the slope
x2-x1

4-(-4)=8
0-2=-2

8/-2=-4
So the slope should be -4.

Since the y-intercept is shown in (0,4), the y-intercept is 4.

6 0

3 years ago

2124 divided by 0.06

Juliette [100K]

The answer is 35400 :)

5 0

3 years ago

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ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

7 0

3 years ago