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Mila [183]
3 years ago
11

Sorry Guys, Angle 12 & 10 are effectively corresponding angles, but angle 10 & 7 are alternate interior angles. Anyways,

Angle 12 & 10 are congruent and 10 & 7 are congruent. At the end, the three angles 12, 10, and 7 have the same measure. If we put it otherwise, the line B is intersecting line D which form right angles equals to 90 degrees, so angle 12 = 90, and the same happens with angle 10 and 7, so the three angles are congruent, but at the same time, angle 7 is supplementary with angle 12 because their sum is equal to 180, (90 + 90 = 180). If you think from different angles is hard to choose the right answer, so what I guess is that we don't need to take into account the angle 10, just the fact that line A intersect line C, and Line B intersect line D forming right angles, and that angle 7 and 12 are right angles which sum equals 180, therefore, we could say that they are supplementary angles, but also congruent because they measure the same, so at the end, I don't know what answer to choose. Both seems correct to me.
Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0

Answer:

d

Step-by-step explanation:Angle 12 & 10 are effectively corresponding angles, but angle 10 & 7 are alternate interior angles. Anyways, Angle 12 & 10 are congruent and 10 & 7 are congruent. At the end, the three angles 12, 10, and 7 have the same measure. If we put it otherwise, the line B is intersecting line D which form right angles equals to 90 degrees, so angle 12 = 90, and the same happens with angle 10 and 7, so the three angles are congruent, but at the same time, angle 7 is supplementary with angle 12 because their sum is equal to 180, (90 + 90 = 180). If you think from different angles is hard to choose the right answer, so what I guess is that we don't need to take into account the angle 10, just the fact that line A intersect line C, and Line B intersect line D forming right angles, and that angle 7 and 12 are right angles which sum equals 180, therefore, we could say that they are supplementary angles, but also congruent because they measure the same, so at the end,

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GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
What is 0.5 L/S= M/L
ch4aika [34]

Answer:

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snow_tiger [21]

Answer:

A) experimental

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   Factor level combinations:

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C) Within the subject : 24 students

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Step-by-step explanation:

A) The study is experimental because of the random assignment of two different types of instruction to the students which will control/affect the technique of teaching without just observing the performance of the students from the side

B) The important factors are : Type of instruction, scores and  High schools,

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   Factor level combinations:

  Level 1 : computer and standard based combination

C) Within the subject : 24 students

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D) The dependent measure  is the score of the test

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Let's say the time (in days) needed by the eleven workers is t,

5*20 = (3*10) + (14*t)

100 = 30+14t

70 = 14t

5 = t

It will take the eleven-workers 5 more days to finish the road.

8 0
2 years ago
One of the lengths of a leg on a right angled triangle is 15 ft the length of the hypotenuse is 17 ft find the length of the oth
Alla [95]
The length of the other leg should be 8ft
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3 years ago
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