Answer:
Step-by-step explanation:
Hello!
Given the probabilities:
P(A₁)= 0.35
P(A₂)= 0.50
P(A₁∩A₂)= 0
P(BIA₁)= 0.20
P(BIA₂)= 0.05
a)
Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)
Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.
b)
Considering that
you can clear the intersection from the formula
and apply it for the given events:


c)
The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:
P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095
d)
The Bayes' theorem states that:

Then:


I hope it helps!
The answer is 43 when you add 29 back to 57 then divide by 2
Answer:
D i think sorry if im wrong
Step-by-step explanation:
-2 - 12=14 becaue if you take negetive number and turn it to a positive number you will add it and then put back negetive sigh again
sorry if i did not explain this right i tried
Answer:
42
Step-by-step explanation:
Answer:
f(1/a) = 1/a² + 2/a + 1
Step-by-step explanation:
Step 1: Define
f(x) = x² + 2x + 1
f(1/a) is x = 1/a
Step 2: Substitute and Evaluate
f(1/a) = (1/a)² + 2(1/a) + 1
f(1/a) = 1/a² + 2/a + 1