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-BARSIC- [3]
3 years ago
15

How to subtract percentages that are fractions

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0
"you can convert the percent to a fraction or decimal. While you might need to subtract a percent from a percent when working in finance, if you are working on homework you more likely will come across problems where you need to subtract a percent from a whole number."
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gogolik [260]
They are all even numbers
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3 years ago
Someone help please.
AnnyKZ [126]

Answer:

Translation (the +5)

Dilation (the x 4)

Compression (the 3 to 1/3, and the x to 2-x)

Step-by-step explanation:

Brainliest, please!

5 0
3 years ago
You use the Internet to purchase 9 tickets for a concert The tickets are $22 each you have to play a handling fee of $3 per tick
Naddik [55]

Answer: $206

Step-by-step explanation: 9(22)+8. 9 is the 9 tickets 22 is the cost of each ticket so they multiply to find the total cost of all tickets. and 8 from shipping and handling.

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2 years ago
Urgent help pleaseeeeeee
Helga [31]

Answer:

2x - 10 = 10 - 3x

Simplifying

2x + -10 = 10 + -3x

Reorder the terms:

-10 + 2x = 10 + -3x

Solving

-10 + 2x = 10 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.

-10 + 2x + 3x = 10 + -3x + 3x

Combine like terms: 2x + 3x = 5x

-10 + 5x = 10 + -3x + 3x

Combine like terms: -3x + 3x = 0

-10 + 5x = 10 + 0

-10 + 5x = 10

Add '10' to each side of the equation.

-10 + 10 + 5x = 10 + 10

Combine like terms: -10 + 10 = 0

0 + 5x = 10 + 10

5x = 10 + 10

Combine like terms: 10 + 10 = 20

5x = 20

Divide each side by '5'.

x = 4

Simplifying

x = 4

3 0
2 years ago
Read 2 more answers
11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *
kompoz [17]

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

3 0
3 years ago
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