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pashok25 [27]
2 years ago
10

A video game customers to rent games for $4.75 each. Customers can also buy a membership for $54 annually, and video games would

only cost $2.50 each. Find the number of video games a customer would have to rent in a year in order for the two options to be equal
Mathematics
1 answer:
Firdavs [7]2 years ago
5 0

Given:

A video game customers to rent games for $4.75 each.

Customers can also buy a membership for $54 annually, and video games would only cost $2.50 each.

To find:

The number of video games a customer would have to rent in a year in order for the two options to be equal.

Solution:

Let x be the number of video games.

A video game customers to rent games for $4.75 each. So, the total cost is

C_1(x)=4.75x

Customers can also buy a membership for $54 annually, and video games would only cost $2.50 each. So, the total cost is

C_2(x)=54+2.50x

Now, C_1(x)=C_2(x), if the rent in a year for the two options to be equal.

4.75x=54+2.50x

4.75x-2.50x=54

2.25x=54

Divide both sides by 2.25.

x=\dfrac{54}{2.25}

x=24

Therefore, the rent in two options are equal for 24 video games.

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