Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60
There should be 45 players that have played before
9.015 that is the decimal form, 1803/200 is fraction form.
ΔADC is a right angle triangle, we will use the Pythagorus Theorem to find the length CD.
Formula of the Pythagorus Theorem :
⇒ a² + b² = c²
⇒ AD² + CD² = AC²
The value of AD is 54 and the value of AC is 90:
54² + CD² = 90²
Solve for CD:
54² + CD² = 90²
CD² = 90² - 54²
CD² = 5184
CD = √5184
CD = 72
ΔADC is also a right angle triangle, we will use the Pythagorus Theorem to find the length BD.
Formula of the Pythagorus Theorem :
⇒ a² + b² = c²
⇒ BD² + CD² = BC²
The value of CD is 72 and the value of BC is 97:
BD² + 72² = 97²
Solve for BD:
BD² = 97² - 72²
BD² = 4225
BD = √4225
BD = 65
Answer: The length of BD is 65 units.
In standard form the answer will be if you go by (Ax+by=c )then I must say it's 3x-7y=9