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3 years ago

Ashlee was born on 12/24/2002. How many eight-digit codes could she make using the digits in her birthday?

Mathematics

1 answer:

svp [43]3 years ago

7 0

Answer:

840

Step-by-step explanation:

Given the date:

Birth date = 12/24/2002

Number of digits = 8 = 8! = (8*7*6*5*4*3*2*1) = 40320

Repeated digits :

digit 2 = 4 times = 4! = (4 * 3 *2 * 1) = 24

digit 0 = 2 times = 2! = 2*1 = 2

Therefore the number of 8 digit codes that can be formed is :

8! / (4! * 2!)

40320 / (24 * 2)

40320 / 48

= 840

Hence, 840 8 digit codes can be formed

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15 50
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3 years ago

The yearly expenses for the Glenn family are represented in the circle graph. The Glenn’s have just purchased a new car. A new c

tiny-mole [99]

Answer:

Car: 18.4% Other: 4.9%

Step-by-step explanation:

Glenn family yearly total expenses are

$\$8,600+\$4,800+\$5,400+\$2,400+\$7,000+\$1,800=\$30,000$

Other expenses are $7,000.

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Now, the expenses for the following two categories are

Car - $5,520

Other - $7,000 - $5,520 = $1,480

Percentage:

Car:

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Other

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4 0

3 years ago

Plz help and show work plz

MrRa [10]

Answer:

3rd option

Step-by-step explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (- 1, - 25 ) , then

f(x) = (x - (- 1) )² - 25 , that is

= (x + 1)² - 25 ← expand using FOIL

= x² + 2x + 1 - 25

= x² + 2x - 24

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Answer:

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Step-by-step explanation:

The 3rd graph C

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