This is a problem you need to solve using logs. When you use logs you can "pull" the exponents down in front of the log to get a new equation that looks like this: 2x^3 + x^2 log 81 = 6x - 3 log 27. Now divide both sides by log 81 and 6x - 3 simultaneously to get (2x^3 + x^2)/(6x - 3) = (log 27)/(log 81). If you do the log math on the right side you get .75. Now multiply both sides by 6x-3 to get 2x^3+x^2 = .75(6x-3). If you distribute that out on the left side you'll get 2x^3+x^2=4.5x-2.25. Now move everything over to the left side and set the whole thing equal to 0: 2x^3+x^2-4.5x+2.25=0. When you solve for x, you are in essence factoring, so do this by grouping: x^2(2x+1)-2.25(2x+1). Now finally factor out the 2x+1 to get (2x+1)(x^2-2.25). You're not done yet though cuz you need to solve each of those for x: 2x+1=0, and x= -1/2; x^2=2.25, and x=+/- 1.5. So all the values for x here are -1/2, 1.5, and -1.5
The solution of the equation is 
Step-by-step explanation:
To simplify an equation of x
- Simplify each side of the equation
- Collect x in side and the numerical terms in the other side
- Find the value of x
∵ The equation is 
- Multiply all terms of the equation by 4 to cancel the denominator
of the 2nd term in the left hand side
∵ The equation is 
∴ 8x + (1 - x) = 12
∴ 8x + 1 - x = 12
- Add like terms
∴ (8x - x) + 1 = 12
∴ 7x + 1 = 12
- Subtract 1 from both sides
∴ 7x = 11
- Divide both sides by 7
∴
The solution of the equation is
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This is a right triangle, so AC is a hypotenuse.
The other angles are each 45 degrees, so the legs AB and BC are equal length.
a^2 + b^2 = c^2
a = b
2a^2 = (5sqrt2)^2 = 50
a^2 = 25
a = 5
Answer: 5
I am not sure but it is right if your question is right.
Answer:
Step-by-step explanation:
they want to know the high and low quiz scores... that's all
