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AnnyKZ [126]
3 years ago
8

A subduction zone is where one plate is pulled under the edge of another and occurs in convergent plate boundaries. Which type o

f crusts are involved in the subduction zone?
a. continental-continental
b. continental-oceanic
c. oceanic-oceanic
Physics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

b. Continental-oceanic

Explanation:

The Earth's crust has been divided into a series of plates. These plates move at a different rate or speed in different directions.

These plates are divided by the boundary between them which are of three types: convergent, transform and divergent.

The convergent boundaries are the one which moves toward each other and the based on the crust they are of three types: continent-continent, ocean-ocean and ocean-continent.

In ocean-continent boundaries, the oceanic plate is denser compared to the continental plate is lighter as a result of which during the process of subduction the oceanic plate sinks beneath the continental plate towards the mantle and melts.

Thus, Option-B is the correct answer.

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A 60 W light bulb has a resistance of 880 Ω
Andreas93 [3]

<h2>\bf{ \underline{Given:- }}</h2>

\sf{• \:  Power \:  (P) = 60 \:  w}

\sf{•  \: Resistance \:  (R) = 880  \: Ω}

\\

<h2>\bf{ \underline{To \:  Find :- }}</h2>

\sf• \:  The  \: Current \:  (I).

\\

\huge\bf{ \underline{ Solution :- }}

\sf We  \: know  \: that,

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\rightarrow \sf 60 = I^{2}  \times 880

\rightarrow \sf  \frac{60}{880} = I^{2}

\rightarrow \sf  I^{2}   = 0.0681

\rightarrow \sf  I   =  \sqrt{0.0681}

\rightarrow \sf  I   =  0.261 \:  \: (approx.)

\\

\bf The \:   \: value \:  \:  of \:  \:  I  \:  \:   is \:  \:  0.261 \:  \: Amps. \:  \: (approx.)

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3 years ago
A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =
Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

v = \omega R\\a = \alpha R

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft

One revolution is equal to the circumference of the drum. So, total number of revolutions is

x / (2\pi R) = 6/(\pi R)

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2

b) a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2

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4 years ago
What are 3 reasons gravity is important? Answer quickly please
allsm [11]

Answer:

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Explanation:

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3 years ago
A ball has a positive momentum. What type of energy must it have? Explain
valentina_108 [34]

Answer:

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A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.
Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

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extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

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n = S_n / car length

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