when we find the distance we will add all the blocks so
distance = 6+6+4
distance = 14blocks
when we find the displacement we will add and minus too
As you can read he goes to the south 6 and to north 6 so he leave that place and back to the place again so the displacement is 0. and again he goes to the west 4 blocks so the displacement = <em><u>4blocks</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>west</u></em>
Part A.
To get the acceleration of the system we consider the two blocks as a single mass. For this situation we have, from Newton's second law, that:
where T is the tension in the upper sting and W is the weight of the system. Solving the equation for a we have:
Therefore the acceleration of the system is 2.42 meters per second per second.
Part B.
Now, that we have the acceleration of the system we analyze the lower block individually; for this block the equation of motion is:
where T' is the tension in the lower rope, W' is the weight of the lower block and m2 is its mass. Solving for the tension we have that:
Therefore the tension in the lower rope is 2.93 N
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
This phenomenon is called the Bragg scattering. The working equation used for this is:
λ = 2dsinθ
where
λ is the wavelength and θ is the incident angle
0.240nm = 2dsin(24.5°)
Solving for d,
<em>d = 0.29 nm</em>
The first one is the light bends sheikh is known as refraction