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pogonyaev
4 years ago
14

Two horizontal curves on a bobsled run are banked at the same angle, but one has twice the radius of the other. The safe speed (

no friction needed to stay on the run) for the smaller radius curve is v. What is the safe speed on the larger radius curve?
Physics
1 answer:
iren [92.7K]4 years ago
4 0

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}................ii

form i and ii we can write

v^2= \frac{1}{2} u^2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

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zloy xaker [14]
3 is 3.81 meters

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6 0
3 years ago
Calculate the percentage of an iceberg submerged beneath the surface of the ocean given that the density of ice is 916.3kg/m3 an
pogonyaev

Answer:

The percentage of an iceberg submerged beneath the surface of the ocean = 89.67%

Explanation:

Let V be the total volume of the iceberg

Let x be the volume of iceberg submerged

According to Archimedes principle,

weight of the iceberg = weight of the water displaced (that is, weight of x volume of water)

Weight of the iceberg = mg= ρ(iceberg) × V × g

Weight of water displaced = ρ(fluid) × x × g

We then have

ρ(iceberg) × V × g = ρ(fluid) × x × g

(x/V) = ρ(iceberg) ÷ ρ(fluid) = 916.3 ÷ 1021.9 = 0.8967 = 89.67%

Hope this Helps!!!!

6 0
3 years ago
Please help me
RSB [31]
The potentially harmful effects of mining can be reduced by A. Flushing mines with water.
5 0
3 years ago
A beam of protons enter the electric field of magnitude E = 0.5 N/C between a pair of parallel plates. There is a magnetic field
HACTEHA [7]

Answer:

0.217 m/s

Explanation:

The protons in the beam passes undeflected when the electric force is equal to the magnetic force:

qE = qvB

where

q is the proton's charge

E is the magnitude of the electric field

v is the speed of the protons

B is the magnitude of the magnetic field

Re-arranging the equation,

v=\frac{E}{B}

And by substituting

E = 0.5 N/C

B = 2.3 T

We find

v=\frac{0.5}{2.3}=0.217 m/s

3 0
3 years ago
A 2.26 kg book is dropped from a height 1.5m what is its acceleration
Arada [10]
The answer is 9.8 ms^-2, because there is only one force acting on the object so the acceleration will be numerically equal to the gravitational field strength.
4 0
3 years ago
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