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katrin [286]
3 years ago
15

2. Calculate the mass of Kool-Aid needed to make 0.1 L solutions at the following concentrations: a. 0.1 M b. 0.2 M c. 0.3 M d.

0.4 M e. 0.5 M
Chemistry
1 answer:
murzikaleks [220]3 years ago
4 0
477889654 that the mass
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Given a sample of poly[ethylene-stat-(vinyl acetate)] A.Calculate the mean repeat unit molar mass for a sample of poly[ethylene-
AlladinOne [14]

Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

so

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05  d/mol

moles of Ethylene  = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate X_{V} = moles of vinyl acetate / total  moles

X_{V} = (0.1498 mol / 3.255 mol) × 100

X_{V}  = 4.6%

mole percent of Ethylene X_{E} = moles of Ethylene / total  moles

X_{E}  = (3.1052 mol / 3.255 mol) × 100

X_{E}  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑X_{i}M_{i}

where X_{i} is the fraction ratio and M_{i} is the molecular  weight

so or the PEVA

mean repeat unit molar mass M = ( X_{V}M_{V}) + ( X_{E}M_{E})

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

DP_{n} = \frac{M_{n} }{M}

where M_{n} is the number average molecular weight ( 39,870 g/mol )

so we substitute

DP_{n} = 39,870 g/mol / 30.72 g/mol

DP_{n}  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

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