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3 years ago

Chocolate candy melting in your hand is what type of heat transfer

Chemistry

1 answer:

gregori [183]3 years ago

6 0

The answer to that is: Conduction

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Question 12 of 15

Vladimir [108]

Answer:

A. The reactants are changed to form the products.

Explanation:

Chemical reactions are reactions that involves a change in the chemical composition of substances involved while a nuclear reaction is the process of fusing together or splitting the nucleus of an atom. According to this question, matter is said to undergo both types of reaction.

However, one similarity in both chemical and nuclear reactions is that substances called REACTANTS are changed to form PRODUCTS. In nuclear reaction, the atoms joined or split are the reactants while the ones formed are the products.

8 0

3 years ago

What volume of a 0.295 M nitric acid solution is required to neutralize 24.8 mL of a 0.107 M potassium hydroxide solution

KengaRu [80]

Answer: 9.00 mL

Explanation:

$M_{A}V_{A}=M_{B}V_{B}\\(0.295)V_{A}=(0.107)(24.8)\\V_{A}=\frac{(0.107)(24.8)}{(0.295)} \approx \boxed{9.00 \text{ mL}}$

4 0

2 years ago

A weak acid is titrated with 0.1236 M NaOH. From the titration curve you determine that the equivalence point occurs after exact

MrRa [10]

<u>Answer:</u> The volume of NaOH required at the half-equivalence point is 6.21 mL

<u>Explanation:</u>

The chemical equation for the reaction of a weak acid with NaOH follows:

$HA+ NaOH\rightarrow NaA+H_2O$

From the equation, we can say that NaOH and weak acid is present in a 1 : 1 ratio.

We are given:

Volume of NaOH required at equivalence point = 12.42 mL

The volume of NaOH required at half-equivalence point will be = $\frac{12.42mL}{2}=6.21mL$

Hence, the volume of NaOH required at the half-equivalence point is 6.21 mL

7 0

3 years ago

What mass of Ca(OH)2 is needed to make 1250ML of a .75M solution?

Setler79 [48]

Answer:

69.4kg

Explanation:

mole =volume/1000 * mole conc.

=1250/1000 * 0.75

mole =0.9

:• mole =mass /molar mass

mass =0.9*[40+32+2]

=69.4kg

5 0

3 years ago

In the protonated form of lysine, the positive charge is localized on one nitrogen atom. In the protonated form of arginine, the

oksano4ka [1.4K]

Answer:

$pK_a$ of arginine is higher than that of lysine.

Explanation:

1. According to the Bronsted-Lowry acid-base theory, a stronger base will have a weak conjugate acid.

The positive charge is more stable on $sp^3$ hybrid atom as compared to $sp^2$ hybrid atom.

Therefore, arginine is more basic as compared to lysine.

2. Moreover, 3 nitrogen atoms are present in arginine that has the capability to accept acidic protons as compared to the one nitrogen that is present in lysine.

Higher the $pK_a$ , higher will be the basicity.

Therefore, $pK_a$ of arginine is higher than that of lysine.

7 0

3 years ago