A force of 70 N is inclined at an angle
1 answer:
Answer:
The horizontal component of the 70 N force = 35·√3 N
The vertical component of the 70 N force = 35 N
Explanation:
The magnitude of the given force, F = 70 N
The angle of inclination of the given force to the horizontal, θ = 30°
By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, , as follows;
The horizontal component of the given force = Fₓ = F × cos(θ)
Substituting the values, we have;
The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N
The vertical component of the given force = = F × sin(θ)
Substituting the values, we have;
The vertical component of the 70 N force, = 70 × sin(30°) = 35 N.
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Answer:
<em>The range is 35.35 m</em>
Explanation:
<u>Projectile Motion</u>
It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:
The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:
The range is 35.35 m