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oksian1 [2.3K]
3 years ago
6

If a body starts moving from rest itsinitial velocity isų Vzerom/s​

Physics
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:

zero

When a Body start a from rest ,its initial velocity is zero.

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Density is a chemical property of matter.<br> TRUE<br> FALSE
kakasveta [241]

Answer:

False

Explanation:

Density is a physical property of matter.

5 0
3 years ago
Read 2 more answers
An object weigh 40N in air ,weigh 20N when submerged in water,and 30N when submerged in a liquid of unknown liquid density.what
muminat

Answer:

The density is  \rho_u  =500 kg /m^3

Explanation:

From the question we are told that

    The weight in air is  W_a =  40 \ N

     The weight in water is  W_w =  20 \ N

     The weight in a unknown liquid is  W_u  =  30  \ N

Now according to Archimedes principle the weight of the object in water is mathematically represented as

       W_w =  W_a -m _w g

Where  m_w is he mass of the water displaced

 substituting value

       m_w g  =  40 -20

      m_w g  = 20 \ N --- (1)

Now according to Archimedes principle the weight of the object in unknown  is mathematically represented as

       W_u =  W_a -m _u g

Where  m_u is he mass of the unknown liquid  displaced

 substituting value

       m_u g  =  40 -30

      m_u g  = 10 \ N ---(2)

dividing equation 2 by equation 1

      \frac{m_ug}{m_wg}  =  \frac{10}{20}

     \frac{m_u}{m_w}  =  \frac{1}{2}

=>  m_u =  0.5 m_w

Now since the volume of water and liquid displaced are the same then

      \rho _u =  0.5 \rho_w

This because

         density =  \frac{mass}{volume}

So if  volume is constant

         mass = constant * density

Where \rho_u is the density of the liquid

     and  \rho_ w is the density of water which is a constant with a value \rho_w = 1000 kg/m^3

So

        \rho_u  = 1000*0.5

        \rho_u  =500 kg /m^3

7 0
3 years ago
A 5.00 g object moving to the right at 20.0 cm/s makes an elastic head-on collision with a 10.0 g object that is initially at re
marusya05 [52]

Answer: a) 6.67cm/s b) 1/2

Explanation:

According to law of conservation of momentum, the momentum of the bodies before collision is equal to the momentum of the bodies after collision. Since the second body was initially at rest this means the initial velocity of the body is "zero".

Let m1 and m2 be the masses of the bodies

u1 and u2 be their velocities respectively

m1 = 5.0g m2 = 10.0g u1 = 20.0cm/s u2 = 0cm/s

Since momentum = mass × velocity

The conservation of momentum of the body will be

m1u1 + m2u2 = (m1+m2)v

Note that the body will move with a common velocity (v) after collision which will serve as the velocity of each object after collision.

5(20) + 10(0) = (5+10)v

100 + 0 = 15v

v = 100/15

v = 6.67cm/s

Therefore the velocity of each object after the collision is 6.67cm/s

b) kinectic energy of the 10.0g object will be 1/2MV²

= 1/2×10×6.67²

= 222.44Joules

kinectic energy of the 5.0g object will be 1/2MV²

= 1/2×5×6.67²

= 222.44Joules

= 111.22Joules

Fraction of the initial kinetic transferred to the 10g object will be

111.22/222.44

= 1/2

3 0
3 years ago
If you swing an object on the end of a string around a circle, the string pulls on the object to keep it moving in a circle. Wha
emmainna [20.7K]

Answer:

B

Explanation:

4 0
2 years ago
During metamorphism, what is the major effect of chemically active fluids?
xz_007 [3.2K]

Answer:

Option b

Explanation:

Metamorphism is the process where the variation of the geological texture resulting from the different arrangement of the minerals or the variation of minerals in protoliths, i.e., pre- existing rocks take place such that there occurs no change in state of the protolith, i.e., it does not melt into magma.

The change takes place as a result of the presence of chemically active fluids, heat and pressure.

There is a reaction between the chemically active fluid and the rock through which it passes and promotes the movement of the dissolved ions of silicate and promotes the growth of the mineral grains.

7 0
3 years ago
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