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ki77a [65]
2 years ago
12

Jan spent 3 3/4 hours doing homework last week. She spent

Mathematics
2 answers:
olchik [2.2K]2 years ago
5 0

Answer:

6/4

Step-by-step explanation:

Schach [20]2 years ago
5 0

Answer:

Exact Form:

3/2

Decimal Form:

1.5

Mixed Number Form:

1 1/2

Step-by-step explanation:

You might be interested in
Plz help I’ll mark you
timurjin [86]

Answer:

A 1/2

Step-by-step explanation:

Ratio of short length to hypotenuse

= cos60

= 1/2

4 0
3 years ago
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
3 years ago
if a line contains a the point (0,-1) and has a slope of 2 which of the following points also lies on the line
Fudgin [204]

Answer:

I think 1 1

Step-by-step explanation:

7 0
3 years ago
3 + 1 < 10 solve, then graph the solution
ryzh [129]

           3 + 1 < 10

There's no question there, and nothing to solve.  That's a simple statement
which, after simplifying it slightly, says " 4 < 10 ".

A statement with which, I'm sure, we can all agree.


3 0
3 years ago
Simplify 3(x+2)-9x+5
Nimfa-mama [501]
It would be...
-6x+11
6 0
3 years ago
Read 2 more answers
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