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3 years ago

Write the equation of the line that goes through (-4,13) and (8,49).

Mathematics

1 answer:

algol [13]3 years ago

4 0

Answer:

y=3x +25

Step-by-step explanation:

First calculate the slope:

m = (y1 - y2)/(x1-x2)

m = (49 - 13)/(8-(-4))

m= 36/12 = 3

so we have

y = 3x + b

subtitute a point:

49=3(8) + b

b=25

the equation is y=3x +25

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Quiz scores of statistics students were obtained by a teacher and listed below. Construct a frequency distribution beginning wit

DanielleElmas [232]

Answer:

The frequency distribution is

S/N Class limit Frequency

1 0-2 4

2 3 -4 1

3 5-6 2

4 7-8 2

5 9 - 10 0

6 11 - 12 0

The value for value upper class boundary of the fifth class is $CB_5 = 10.5$

Step-by-step explanation:

From the question we are told that

The lower class limit is 0

The class width is 2

The scores is 8,6,2,4,2,0,2,6,7

The frequency distribution is

S/N Class limit Frequency

1 0-2 4

2 3 -4 1

3 5-6 2

4 7-8 2

5 9 - 10 0

6 11 - 12 0

Generally the upper class boundary of the fifth class is mathematically represented as

$CB_5 = \frac{10 + 11}{2}$

$CB_5 = 10.5$

8 0

3 years ago

A number is called evil if it has 666 in it. How many 7 digit numbers are evil?

defon

Step-by-step explanation:

There are 5 different positions of 666:

666////

/666///

//666//

///666/

////666

The forward dashes represent any number from 0 to 9.

Case 1: "666////"

Number of ways = 10⁴ = 10,000.

Case 2: The other positions.

Since the 1st forward dash cannot be 0 (leading digit),

Number of ways for each position = 9 * 10³ = 9,000

Number of ways for all 4 positions = 9,000 * 4 = 36,000.

Total evil numbers = 10,000 + 36,000 = 46,000.

5 0

2 years ago

Samantha is studying the population growth of an endangered birth. The growth can be modeled by the equation B(t) 100 + 3/5t^5 ,

solong [7]

The value of the population of the growth of an endangered birth after 5 years is 1975

<h3>How to determine the population after 5 years?</h3>

The population function is given as:

B(t) = 100 + 3/5t^5

At 5 years, the value of t is 5

So, we have

t = 5

Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5

This gives

B(5) = 100 + 3/5 * 5^5

Evaluate the exponent

B(5) = 100 + 3/5 * 3125

Evaluate the product

B(5) = 100 + 1875

Evaluate the sum

B(5) = 1975

Hence, the value of the population of the growth of an endangered birth after 5 years is 1975

Read more about exponential functions at:

brainly.com/question/2456547

#SPJ1

4 0

1 year ago

Plzzzzzzzzzzzzzzzzzzz help

liq [111]

Answer:

Step-by-step explanation:

1/2 b h

1/2×10×5=25

so i guess the ans is 25 thats all I know

u take 1/2 base ×height

4 0

3 years ago

Read 2 more answers

How do u do 2 over 3 =A over 60 PLZ NO LINKS THANKS

Ivanshal [37]

Hey there!

2/3 = a/30

First: you have to CROSS MULTIPLY the given numbers

2(30) = 3(a)

2(30) = 60

3(a) = 3a

New EQUATION: 3a = 60

Second: DIVIDE 3 to BOTH SIDES

3a/3 = 60/3

CANCEL out: 3/3 because that gives you 1

KEEP: 60/3 because that helps you solve for your a-value

60/3 = a

60/3 = 20

Therefore, your answer is: a = 20

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

6 0

2 years ago