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KengaRu [80]
3 years ago
11

F(x) = 3x2 – x + 5; g(x) = 2x – 3. find f(x)-g(x)​

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0

Answer:

f(x) - g(x) = 3x² - 3x + 8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Distributive Property

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 3x² - x + 5

g(x) = 2x - 3

<u>Step 2: Find f(x) - g(x)</u>

  1. Substitute in function values:                                                                          f(x) - g(x) = 3x² - x + 5 - (2x - 3)
  2. [Distributive Property] Distribute negative:                                                    f(x) - g(x) = 3x² - x + 5 - 2x + 3
  3. [Subtraction] Combine like terms (x):                                                              f(x) - g(x) = 3x² - 3x + 5 + 3
  4. [Addition] Combine like terms:                                                                        f(x) - g(x) = 3x² - 3x + 8
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Answer:

2.50

Step-by-step explanation:

Given

(x_1,y_1) = (-1,0.8)

(x_2,y_2) = (0,2)

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(x_4,y_4) = (2,12.5)

Required

The rate of change (b)

The above graph is represented as:

y = ab^x

For: (x_2,y_2) = (0,2);

We have:

y = ab^x

2 = a * b^0

2 = a *1

2 = a

a = 2

For (x_3,y_3) = (1,5),

We have:

y = ab^x

5 = a * b^1

5 = a * b

Substitute a = 2

5 = 2 * b

Divide by 2

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Answer:

\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k​, the vector projection of B unto a is expressed as proj_ab = \dfrac{b.a}{||a||^2} * a

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k  =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||²  = 130

proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\

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Answer:

Option B.

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The triangle is rotated 270° clockwise using the origin as the center of rotation. So, rule of rotation is defined as

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Now,

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So, the vertices of image are G'(3,2), F'(1,4) and H'(-1,1).

Therefore, the correct option is B.

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