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2 years ago

F(x) = 3x2 – x + 5; g(x) = 2x – 3. find f(x)-g(x)

Mathematics

1 answer:

Sonbull [250]2 years ago

8 0

Answer:

f(x) - g(x) = 3x² - 3x + 8

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 3x² - x + 5

g(x) = 2x - 3

Step 2: Find f(x) - g(x)

Substitute in function values: f(x) - g(x) = 3x² - x + 5 - (2x - 3)
[Distributive Property] Distribute negative: f(x) - g(x) = 3x² - x + 5 - 2x + 3
[Subtraction] Combine like terms (x): f(x) - g(x) = 3x² - 3x + 5 + 3
[Addition] Combine like terms: f(x) - g(x) = 3x² - 3x + 8

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Answer:

(a)

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(b)

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(c)

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(d)

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Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

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(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

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(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

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F(x) = 3x2 – x + 5; g(x) = 2x – 3. find f(x)-g(x)​

F(x) = 3x2 – x + 5; g(x) = 2x – 3. find f(x)-g(x)