If you divide the 2 in 3 you get .6 and if you divide 2 in 5 ou get ,4 now add them you and get 1 now add that 1 to 30 your answer should be 31
Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
Answer:
-2
Step-by-step explanation:
The system shown at the right has no solution, as the grahs never intersect.
On the other hand, the line and the parab. at the left do intersect, and the points of intersection are (-3,0) and (6,6).
He can make 8 bows because 4 1/4 = 1 so 4×2=8
