3n=15-(6/3)
3n=15-2
3n=13
n=(13/3)
2x^2 + 9x + 4 = 0
x^2 + 9/2*x + 2 = 0
x = - 9/4 +- √(81/16 - 32/16) = - 9/4 +- 7/4
x1 = - 1/2
x2 = - 4
9514 1404 393
Answer:
C. 3x∛(y²z)
Step-by-step explanation:
The relevant rules of exponents are ...
![\sqrt[n]{a^m} = a^\frac{m}{n}\\\\(a^b)^c=a^{bc}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20a%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D)
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Your expression can be rewritten and simplified as follows.
![\displaystyle\sqrt[3]{27x^3y^2z}=(3^3x^3y^2z)^\frac{1}{3}=3xy^\frac{2}{3}z^\frac{1}{3}=3x(y^2z)^\frac{1}{3}=\boxed{3x\sqrt[3]{y^2z}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B27x%5E3y%5E2z%7D%3D%283%5E3x%5E3y%5E2z%29%5E%5Cfrac%7B1%7D%7B3%7D%3D3xy%5E%5Cfrac%7B2%7D%7B3%7Dz%5E%5Cfrac%7B1%7D%7B3%7D%3D3x%28y%5E2z%29%5E%5Cfrac%7B1%7D%7B3%7D%3D%5Cboxed%7B3x%5Csqrt%5B3%5D%7By%5E2z%7D%7D)
<span>Find
the speed of each car.
Let a be the first car
Let b be the second car
=> a = x miles per hour
=> b = x + 12 miles per hour
=> 2 (x+ x + 12) = 232 miles per hour
=> 2x + 12 = 232
=> 2x + 12 = 116
=> 2x = 116 - 12
=> 2x / 2 = 104 / 2
=> x = 52 (speed of Car A)
=> 52 + 12 = 64 miles per hour (speed of Car B)</span>
The Semi-Major Axis is half the longest diameter of the ellipse and the Eccentricity gives the shape of the ellipse.
