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3 years ago

Find the area of the figure.( sides meet at right angles.)picture below

Mathematics

1 answer:

Tema [17]3 years ago

5 0

You can divide the figure as follows:

A vertical rectangle, 5 meters tall and 2 meters wide, on the top right.
A horizontal rectangle, 2 meters tall and 5 meters wide, on the bottom left
A 2x2 meters square on the bottom right, where the two rectangles meet.

The area of the rectangles is 5x2=10 meters squared, while the area of the square is 2x2=4 meters squared.

So, the total area is 10+4=14 meters squared.

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3 years ago

What is the volume, in cubic inches, of a rectangular prism with a height of 19 inches, a width of 11 inches, and a length of 4

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3 years ago

Need help its sector area

Paladinen [302]

Area of sector

$= \frac{30}{360} \times \pi \times {(radius)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times {(12)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times 12 \times 12$

so the area = 37.71 square metre

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3 years ago

The solids are similar. Find the surface area of the red solid.

alisha [4.7K]

Answer:

756

Step-by-step explanation:

The ratio of areas is the square of the scale factor.

First, we find the scale factor from the blue solid to the red solid.

scale factor = 6/4 = 3/2

The ratio of areas is the square of the scale factor:

ratio of areas = (3/2)^2 = 9/4

volume of red solid = volume of blue solid * ratio of areas

volume of red solid = 336 m^2 * 9/4 = 756 m^2

Answer: S = 756 m^2

8 0

3 years ago