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ANTONII [103]
3 years ago
5

PLEASE How much voltage is required to run 1.6 A of current through a 2400 resistor? Use AV = IR.

Physics
1 answer:
sergey [27]3 years ago
3 0

Explanation:

from \: ohms \: law \\ voltage \:  \: V =IR  \\  = 1.6 \times 2400  \\  = 3840 \: Volts

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The bridges often have expansion joints to account for the changes in size due to temperature changes. Suppose a bridge is suppo
Helga [31]

Answer:

1.33 cm

Explanation:

L = 32 m, T 1 = 0 degree C , T2 = 32 degree C

Thermal expansion coefficient of steel, α = 13 x 106-6 per degree C

Let ΔL be the increase in length.

ΔL = L x α x ΔT

ΔL = 32 x 13 x 10^-6 (32 - 0)

ΔL = 0.0133 m = 1.33 cm

6 0
3 years ago
How are mixtures essential to living and non living things on earth?
sertanlavr [38]
Let's mention 2 examples of a mixture:

1) blood- blood is a mixture of blood plasma and blood cells. Blood is very important to many forms of life, including humans. It's therefore essential to living things!

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7 0
4 years ago
If f^-1(y) is the inverse of f(x) which statements must be true?
Salsk061 [2.6K]
Let us assume f(x) = 2x - 5
f⁻¹(x) = (x + 5)/2
f(f⁻¹(x)) = 2((x + 5)/2) - 5 = x
f⁻¹(f(x)) = (2x - 5 + 5)/2 = x
The domain of a function is the range of its inverse and vice versa
The range of a function is the domain of its inverse and vice versa
Therefore, statements A, B, D and E are true
6 0
4 years ago
A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
Blababa [14]

Answer:

(B) 1.6 m/s^2

Explanation:

The equation of the forces acting on the box in the direction parallel to the slope is:

mg sin \theta - \mu N = ma (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity, \theta=39^{\circ} being the angle of the incline

\mu N is the frictional force, with \mu = 0.6 being the coefficient of kinetic friction, N being the normal reaction of the plane

a is the acceleration

The equation of the force along the direction perpendicular to the slope is

N-mg cos \theta =0

where mg cos \theta is the component of the weight in the direction perpendicular to the slope. Solving for N,

N=mg cos \theta

Substituting into (1), solving for a, we find the acceleration:

a=gsin \theta- \mu g cos \theta=(9.8)(sin 39^{\circ})-(0.6)(9.8)(cos 39^{\circ})=1.6 m/s^2

6 0
4 years ago
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Temka [501]

Answer:

shiny

Explanation:

6 0
3 years ago
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