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3 years ago

What is the MAIN idea of the section "Green Loses Its Power In Fall"?

Physics

1 answer:

zloy xaker [14]3 years ago

4 0

B is the main answe becuase Keith mecruty dies in the American war by being shot

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The radar system of a navy cruiser transmits at a wavelength of 1.4 cm, from a circular antenna with a diameter of 2.7 m. At a r

Goshia [24]

Answer:

Distance will be 49.34 m

Explanation:

We have given wavelength $\lambda =1.4cm =0.014m$

Diameter of the antenna d = 2.7 m

Range L = 7.8 km = 7800 m

We have to find the smallest distance hat two speedboats can be from each other and still be resolved as two separate objects D

We know that distance is given by $D=\frac{L1.22\lambda }{d}=\frac{7800\times 1.22\times 0.014}{2.7}=49.3422m$

So distance D will be 49.34 m

4 0

3 years ago

1 point

RoseWind [281]

Answer:

Bacteria and Fungus

6 0

3 years ago

A current of I=8.0A is flowing in a typical extension cord of length L=3.00m. The cord is made of copper wire with diameter d=1.

anzhelika [568]

⁻Answer:

Ne=1.8 *10^37

Explanation:

Current density J=Iₐ /(πr²)

= 8/(π* (1.5*10⁻³/2)²)= 4.53*10⁶ A/m²

Drift velocity = J/ne =4.53*10⁶ /(8.5×1028 *1.6×10−19 ) = 3.33 ×10−4 m/s

volume = πr²h= π * (1.5*10⁻³/2)² * 3 = 5.3 ×10−6 m³

$\rho =\frac{m}{ne^{2}} \\\\n=\frac{m}{\rho e^{2}}$

Ne=1.8 *10^37

7 0

4 years ago

Birds resting on high-voltage power lines are a common sight. the copper wire on which a bird stands is 3.5 cm in diameter and c

kiruha [24]

Answer:

$1.0 \cdot 10^{-5}V$

Explanation:

First of all, we need to calculate the resistance of the piece of copper wire between the bird's feet, which is given by

$R=\rho \frac{L}{A}$

where:

$\rho = 1.68 \cdot 10^{-8} \Omega m$ is the resistivity of copper

$L = 2.1 cm = 0.021 m$ is the length of the piece of wire between the bird's feet

$A=\pi r^2$ is the cross-sectional area of the wire, with r being the radius. Since the radius is half the diameter:

$r=\frac{3.5 cm}{2}=1.75 cm=0.0175 m$

the area is

$A=\pi (0.0175 m)^2=9.34 \cdot 10^{-4} m^2$

And the resistance is

$R=(1.68\cdot 10^{-8} \Omega m \frac{0.0175 m}{9.34 \cdot 10^{-4} m^2}=3.15\cdot 10^{-7}\Omega$

And given the current in the wire, I=32 A, we can calculate the potential difference across the bird's body by using Ohm's law:

$V=IR=(32 A)(3.15\cdot 10^{-7} \Omega)=1.0 \cdot 10^{-5}V$

6 0

3 years ago

What is an air mass?

Dennis_Churaev [7]

<span>a body of air with horizontally uniform temperature, humidity, and pressure.</span>

3 0

3 years ago

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