Answer: a= 4.4ms-2
Displacement= 26.95 m
Explanation:
First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.
Answer: The canyon wall is 850 m away from the person
Explanation:
Well, the speed of sound in air at
is defined as
, this can be calculated by the following equation:
(1)
Where:
is the Heat capacity ratio for air
is the Universal Gas constant
is the temperature in Kelvin
is the air molar mass
(2)
Now that we know the speed of sound, we can use the following equation to find the distance between the person and the canyon wall:
(3)
Where:
is the distance between the person and the canyon wall
is the time it takes to the sound wave to travel from the person and then go back
Isolating :
(4)
(5)
Finally:
Answer:
The velocity of the camera is 33.11 m/s.
Explanation:
Given that,
Speed = 10.8 m/s
Altitude = 50 m
Suppose determine the velocity of the camera just before it hits the ground?
We need to calculate the velocity of the camera
Using equation of motion
Where, v = final velocity of camera
u = initial speed of camera
s = distance
Put the value into the formula
The direction will be downward so it is the negative velocity.
Hence, The velocity of the camera is 33.11 m/s.