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3 years ago

7

Find the resistance of a circuit that draws 0.06 amperes with 12 volts applied

2 answers:

Tresset [83]3 years ago

8 0

Answer: 200Ω

Explanation:

$R=\frac{V}{I}$

$R=\frac{12}{0.06} \\R=200$

ipn [44]3 years ago

4 0

Answer:resistance=200ohms

Explanation:

current=0.06amperes

Voltage=12volts

Resistance=voltage/current

Resistance=12/0.06

Resistance=200

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A farsighted boy has a near point at 2.3 m and requires eyeglasses to correct his vision. Corrective lenses are available in inc

tino4ka555 [31]

Answer:

P = 3.5 D

Explanation:

As we know that convex lens is to be used to make the near point of eye to be correct

So we will have

$\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}$

here we have

$d_i = 2.3 m = 230 cm$

$d_o = 25 cm$

now plug in all values into the formula

$-\frac{1}{230} + \frac{1}{25} = \frac{1}{f}$

$f = 28 cm$

now for power of lens

$P = \frac{1}{f}$

$P = \frac{1}{0.28} = 3.5 D$

so the power in dioptre is

P = 3.5 D

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3 years ago

A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a

VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

$r_1 = 45 sin15 \hat i + 45 cos15 \hat j$

$r_1 = 11.64 \hat i + 43.46\hat j$

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

$r_2 = 30 cos15\hat i + 30 sin15 \hat j$

$r_2 = 28.98\hat i + 7.76 \hat j$

now the displacement of the boat is given as

$d = r_2 - r_1$

$d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)$

$d = 17.34 \hat i - 35.7 \hat j$

so the magnitude is given as

$d = \sqrt{17.34^2 + 35.7^2}$

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3 years ago

You find a pressure gauge in the lab and the spec sheet says that the maximum pressure it can read a maximum of 2 inches of wate

Inessa05 [86]

Answer:

Maximum pressure in pascal is 497.84 pa

Explanation:

Pressure is given by $P=\rho g h$

where $\rho$ is density of water = 1000 $kg/m^3$

height of the water $h$ is 2 inches = $2\times 25.4=50.8 mm=50.8\times 10^{-3} m$

Maximum pressure in pascal is

$P=1000\times 9.8\times 50.8\times 10^{-3}\\p=497.84 Pa$

8 0

3 years ago

Just how small do you think an individual atom is

jok3333 [9.3K]

An atom is probably less than 1 nano-meter in size

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3 years ago

Read 2 more answers

You have arrived at the scene of a two car accident. You know the following pieces of information:

Pani-rosa [81]

The initial velocity of car 1 is 20 m/s to the right

The initial velocity of car 2 is zero

The final velocity of car 2 is 10 m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision.

Therefore, we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where:

$m_1 = 2000 kg$ is the mass of the first car

$u_1$ is the initial velocity of the first car

$v_1 = 10 m/s$ is the final velocity of the first car (taking right as positive direction)

$m_2 = 2000 kg$ is the mass of the second car

$u_2 = 0$ is the initial velocity of the second car

$v_2$ is the final velocity of the second car

We also know the initial momentum of car 1, which is

$p_1 =40,000 kg m/s$

And since momentum is the mass times the velocity, we find the initial velocity of car 1:

$u_1 = \frac{p_1}{m_1}=\frac{40,000}{2,000}=20 m/s$

with a positive sign, since the direction is to the right.

Now we can re-arrange the previous equation and solve for v2, the final velocity of car 2:

$v_2 = \frac{m_1 u_1 -m_1 v_1}{m_2} = \frac{(2000)(20)-(2000)(10)}{2000}=10 m/s$

And since the sign is positive, the direction is the same as the initial direction of car 1, so to the right.

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

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3 years ago