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salantis [7]
2 years ago
7

Find the resistance of a circuit that draws 0.06 amperes with 12 volts applied

Physics
2 answers:
Tresset [83]2 years ago
8 0

Answer: 200Ω

Explanation:

R=\frac{V}{I}

R=\frac{12}{0.06} \\R=200

ipn [44]2 years ago
4 0

Answer:resistance=200ohms

Explanation:

current=0.06amperes

Voltage=12volts

Resistance=voltage/current

Resistance=12/0.06

Resistance=200

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A cyclist accelerates from 0m/s to 8m/s in 3 seconds.
garik1379 [7]

Answer:

the rate of acceleration is 2.6666(and so on) if thats your question

Explanation:

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2 years ago
How many forces are acting on a stationary raft floating in a swimming pool A1 B2 or C3
Hitman42 [59]
There are at least two forces on it, and there could be more.

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These two forces must be exactly equal, so that the net
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Horizontal forces:
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But we don't know if there are actually no horizontal forces
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2 years ago
What effect would decreasing the distance between objects have on their gravitational attraction to each other?
Lady_Fox [76]
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5 0
3 years ago
Read 2 more answers
A train increases its speed steadily from 10 m/s to 20 m/s in
rewona [7]

Answer:

15m/s

Explanation:

add the two speeds and divide by 2

10+20=30

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3 0
3 years ago
To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug
Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

\tau = Fr

Where,

F = Force

r = Radius

Replacing we have that,

\tau = Fr

\tau = 21cm (\frac{1m}{100cm})* 550N

\tau = 11.55Nm

The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2

I = 0.394kg\cdot m^2

Finally, angular acceleration is a result of the expression of torque by inertia, therefore

\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}

\alpha = \frac{11.55}{0.394}

\alpha = 29.3 rad/s^2

PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians (\pi / 3), therefore

W = \tau \theta

W = 11.5* \frac{\pi}{3}

W = 12.09J

4 0
3 years ago
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