Answer: The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
Explanation:
Force applied on the golf ball = 
Mass of the ball = 0.05 kg
Velocity with which ball is accelerating = 44 m/s
Time period over which forece applied = t
Newton seconds
The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
1 gallon has 0.133681 cubic feet
Answer:
(a) m = 33.3 kg
(b) d = 150 m
(c) vf = 30 m/s
Explanation:
Newton's second law to the block:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
Data
F= 100 N
a= 3.0 m/s²
(a) Calculating of the mass of the block:
We replace dta in the formula (1)
F = m*a
100 = m*3
m = 100 / 3
m = 33.3 kg
Kinematic analysis
Because the block moves with uniformly accelerated movement we apply the following formulas:
d= v₀t+ (1/2)*a*t² Formula (2)
vf= v₀+a*t Formula (3)
Where:
d:displacement in meters (m)
t : time interval in seconds (s)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
a= 3.0 m/s²
v₀= 0
t = 10 s
(b) Distance the block will travel if the force is applied for 10 s
We replace dta in the formula (2):
d= v₀t+ (1/2)*a*t²
d = 0+ (1/2)*(3)*(10)²
d =150 m
(c) Calculate the speed of the block after the force has been applied for 10 s
We replace dta in the formula (3):
vf= v₀+a*t
vf= 0+(3*(10)
vf= 30 m/s
Answer:
Answered
Explanation:
x= 0.02 m
E_p= 10.0 J
E_p= 0.5kx^2
10= 0.5k(0.02)^2
solving we get
K= 50.0 N/m
Now
E'_p= 0.5kx'^2
E'_p= 0.5×50×(0.04)^2
E'_p=40 J
b) potential energy is a scalar quantity and it only depends magnitude and not direction so it will remain same in compression and expansion both
c) 20 J = 0.5×50,000×x^2
solving
x= 0.028 m
d) k is 50.0 N/m from above calculation
Answer:
a.) F = 3515 N
b.) F = 140600 N
Explanation: given that the
Mass M = 74kg
Initial velocity U = 7.6 m/s
Time t = 0.16 s
Force F = change in momentum ÷ time
F = (74×7.6)/0.16
F = 3515 N
b.) If Logan had hit the concrete wall moving at the same speed, his momentum would have been reduced to zero in 0.0080 seconds
Change in momentum = 74×7.6 + 74×7.6
Change in momentum = 562.4 + 562.4 = 1124.8 kgm/s
F = 1124.8/0.0080 = 140600 N
