Answer:
-4>x and 5≤=x
Step-by-step explanation:
Hope this helps!!!
Two ways:
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1
x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)] if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6] but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/- [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]
x=34 is the correct answer!
notice the tickmarks on the sides, meaning TX = FL, YX = FW and YT = WL, I must say those tickmarks are missing a triplet one |||, but anyhow, they are there, and if that is indeed the case, then S ide S ide S ide.
The distance around a rectangle or a square is as you might remember called the perimeter. The distance around a circle on the other hand is called the circumference. It is calculated as follows:
C = 2pi(r)
From this, we can solve for r and evetually solve for the diameter.
44 = 2pi(r)
r = 7.00
d = 2r
d = 14
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