X+6x=56. 7x=56. Divide each side by 7 to get x=8. So Edna has 48 marbles. Sam has 8 marbles. She has 40 more marbles. Hope this helps! ;)
<h3>
Answer: A. 18*sqrt(3)</h3>
=============================================
Explanation:
We'll need the tangent rule
tan(angle) = opposite/adjacent
tan(R) = TH/HR
tan(30) = TH/54
sqrt(3)/3 = TH/54 ... use the unit circle
54*sqrt(3)/3 = TH .... multiply both sides by 54
(54/3)*sqrt(3) = TH
18*sqrt(3) = TH
TH = 18*sqrt(3) which points to <u>choice A</u> as the final answer
----------------------
An alternative method:
Triangle THR is a 30-60-90 triangle.
Let x be the measure of side TH. This side is opposite the smallest angle R = 30, so we consider this the short leg.
The hypotenuse is twice as long as x, so TR = 2x. This only applies to 30-60-90 triangles.
Now use the pythagorean theorem
a^2 + b^2 = c^2
(TH)^2 + (HR)^2 = (TR)^2
(x)^2 + (54)^2 = (2x)^2
x^2 + 2916 = 4x^2
2916 = 4x^2 - x^2
3x^2 = 2916
x^2 = 2916/3
x^2 = 972
x = sqrt(972)
x = sqrt(324*3)
x = sqrt(324)*sqrt(3)
x = 18*sqrt(3) which is the length of TH.
A slightly similar idea is to use the fact that if y is the long leg and x is the short leg, then y = x*sqrt(3). Plug in y = 54 and isolate x and you should get x = 18*sqrt(3). Again, this trick only works for 30-60-90 triangles.
You can Draw a segment WY connecting the centers<span> of the </span>two circles<span>, and then draw a segment, WS, so that YS + SZ = YZ and WS ⊥ YZ).</span>
Answer:
Option A 90,68
Step-by-step explanation:
see the attached figure to better understand the problem
The figure shows a kite
we know that
A kite properties include
1) two pairs of consecutive, congruent sides
2) congruent non-vertex angles
3) perpendicular diagonals
Find the measure of angle 1
we have that
----> by the diagonals are perpendicular
Find the measure of angle 2
we know that
triangle AEB is congruent with triangle CEB
so
In the right triangle EAB
----> by complementary angles in a right triangle
so
therefore
Answer:
Hence option C is correct...hope this helps you:)
