All categories

2 years ago

Employees at Standard Storage are in the ratio of 2 women to 7 men. If there are 490 men employed,

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

4 0

Proportion women /men = 2/7 = x/490 7x= 2· 490 :7

X = 2·70 = 140

You might be interested in

79=11x+13 <br> Solve each equation by using the properties of equality and justify each step

neonofarm [45]

Solution: X=6

Detailed explanation:

In this problem we're asked to find "x" or the unknown.

The first step is to subtract 11x from both sides.

$---\mapsto\boldsymbol{-11x+79=13}$

Next, subtract 79 from both sides.

$---\mapsto\boldsymbol{-11x=-66}$

To finish this off, divide both sides by -11.

$---\mapsto\boldsymbol{x=6}$

Voila! There's our answer!

<h2><em>Cheers!! ^-^</em></h2>

___________________

Hope I helped. Best wishes.

Reach far. Aim high. Dream big.

___________________

8 0

1 year ago

Read 2 more answers

Can some plz help me

alisha [4.7K]

Answer: red 36 m

Step-by-step explanation: base plus base = 18 / 2 = 9 * 4 = 36 m

3 0

2 years ago

Read 2 more answers

What is the answer some one help me please so i can do this

inna [77]

Answer:

They can buy up to 240 drinks.

Step-by-step explanation:

Let x = number of drinks

The price of 1 drink is 75¢ = $0.75

The price of x drinks is 0.75x

The store gives a discount of $100.

The rice of x drinks is

0.75x - 100

The total price of the drinks must be less than or equal to $80.

0.75x - 100 ≤ 80

Add 100 to both sides.

0.75x ≤ 180

Divide both sides by 0.75

x ≤ 240

Answer: They can buy up to 240 drinks.

6 0

2 years ago

A hunter is at a point on a riverbank. He wants to get to his cabin located 2 Miles North and 8 Miles West. He can travel 5 Mph

miskamm [114]

Answer:

Option A

Step-by-step explanation:

A hunter travels to his cabinet located at 2 Miles North and 8 Miles West.

Let "d" be the distance traveled before reaching the rocky ground at point say "P". Let the cabin be at "C"

The distance between C and P is given by

$\sqrt{(2^2+(8-d)^2}\\$

Let "t" be the time taken to travel distance CP.

$T = \frac{d}{5} + \frac{\sqrt{2^2+(8-d)^2} }{3}$

Minimum time will be when "t" is equal to zero

Differentiating the above equation wrt "d", we get -

$= \frac{1}{5} + \frac{1}{3} (\frac{-2(8-d)}{2\sqrt{2^2+(8-d)^2} } )= 0\\\frac{1}{5} = \frac{1}{3} \frac{(8-d)}{\sqrt{4+(8-d)^2} } \\3\sqrt{4+64+d^2-16d} = 40-5d\\$

On squaring both the sides , we get -

$3\sqrt{4+64+d^2-16d} = 40-5d\\9(68+d^2-16d)= 1600+25d^2 -400d\\612+9d^2-144d=1600+25d^2 -400d\\16d^2-256d+988=0\\d_1 = 9.5\\d_2 = 6.5$

"d" cannot be greater than 8 miles.

Hence, the value of "d" is equal to $6.5$

Option A

8 0

2 years ago

Write an equation in slope intercept

Dafna11 [192]

Answer:

y=1/2x-8

Step-by-step explanation:

7 0

2 years ago